比较具有不同数量元素的两个多维数组

问题描述：

I have two multidimensional arrays with different number of elements:

$complete = array(array("24","G:\TVShows\24"),array("Lost","G:\TVShows\Lost"),array("Game of Thrones","G:\TVShows\Game of Thrones"));
$subset = array(array("24","G:\TVShows\24","English"));

The first one ($complete) is the complete list of my tv shows on disk (name of the show, path to files). The second one ($subset) come from my database and include the spoken language as a third column / element.

I would like to return the shows that I have on disk but that do not appear in databse. How can I compare those to array with different number of elements?

Thank you for your help!

我有两个具有不同元素数的多维数组： p>

  $ complete = array（array（“24”，“G：\ TVShows \ 24”），array（“Lost”，“G：\ TVShows \ Lost”），数组（“权力的游戏”，“G：\  TVShows \权力的游戏“））; 
 $ subset = array（array（”24“，”G：\ TVShows \ 24“，”English“））; 
  code>  pre> 
 \  n 第一个（$ complete）是我在磁盘上的电视节目的完整列表（节目名称，文件路径）。 第二个（$ subset）来自我的数据库，并将口语作为第三列/元素包含在内。 p> 
 
 
我想返回我在磁盘上但没有的节目 出现在数据库中。 如何将这些元素与具有不同元素数量的数组进行比较？ p> 
 
 
感谢您的帮助！ p> 
  div>

答

Since its a multi leveled array, you could use and combine array_map() and serialize()/unserialize(). Consider this example:

$complete = array(
    array("24","G:\TVShows\24"),
    array("Lost","G:\TVShows\Lost"),
    array("Game of Thrones","G:\TVShows\Game of Thrones"),
    array("The Walking Dead","G:\TVShows\The Walking Dead"),
    array("Breaking Bad","G:\TVShows\Breaking Bad"),
    array("Heroes","G:\TVShows\Heroes"),
);

$subset = array(
    array("24","G:\TVShows\24","English"),
    array("The Walking Dead","G:\TVShows\The Walking Dead","English"),
    array("Heroes","G:\TVShows\Heroes","English"),
);

$shows_not_in_db = array();
// properly format the subsets for comparison on complete
foreach($subset as $key_s => $value_s) {
    array_pop($value_s); // remove the last element "English"
    $subset[$key_s] = serialize($value_s);
}

// serialize each complete arrays
$complete = array_map('serialize', $complete);
$shows_not_in_db = array_map('unserialize', array_diff($complete, $subset)); // array diff them, then unserialize

print_r($shows_not_in_db);

Sample Output

Edit: For case insensitive comparisons, you may use this alternative:

$shows_not_in_db = array_map('unserialize', array_udiff($complete, $subset, 'strcasecmp'));

// sample: The walking dead - The Walking Dead

比较具有不同数量元素的两个多维数组

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