您的位置: 首页  >  技术问答  >  preg_match_all没有从php中的文件中获取图像src

preg_match_all没有从php中的文件中获取图像src

分类: 技术问答 • 2022-04-09 20:35:14
问题描述：

I have page image.php

where images are kept in container like below :- Note: There are other Images outside container div too.. i just want images from container div.

    <!DOCTYPE html>
    <head>
        <title>Image Holder</title>
    </head>
    <body>
        <header>
        <a href="#"><img src="http://examepl.com/logo.png"></a>
            <div id="side">
                <div id="facebook"><img src="http://examepl.com/fb.png"></div>
                <div id="twiiter"><img src="http://examepl.com/t.png"></div>
                <div id="gplus"><img src="http://examepl.com/gp.png"></div>
            </div>
        </header>      
        <div class="container">
            <p>SOme Post</p>
            <img src="http://examepl.com/some.png" title="some image" />

            <p>SOme Post</p>
            <img src="http://examepl.com/some.png" title="some image" />

            <p>SOme Post</p>
            <img src="http://examepl.com/some.png" title="some image" />
        </div>
        <footer>
            <div id="foot">
                copyright &copy; 2013
            </div>
        </footer>
    </body>
</html>

and i am trying to fetch only image from my image.php file with preg_match_all, but it returns boolean(false) :(

my php code :-

<?php
$file = file_get_contents("image.php");
preg_match_all("/<div class=\"container\">(.*?)</div>/", $file, $match);
preg_match_all("/<img src=\"(.*?)\">/", $match, $images);

var_dump($images);
?>

Both the files are in root folder , and now i am getting blank page :(

Any help would be great

Thanks

我有页面image.php p>

其中图像保存在容器中 下面： - 注意：容器div外还有其他图像..我只想要容器div中的图像。 p> 

 ＆lt;！DOCTYPE html＆gt; 
＆lt; head＆gt; \  n＆lt; title＆gt;图像持有人＆lt; / title＆gt; 
＆lt; / head＆gt; 
＆lt; body＆gt; 
＆lt; header＆gt; 
＆lt; a href =“＃”＆gt;＆lt; img src =“http：  //examepl.com/logo.png"></a>
＆lt; div id =“side”＆gt; 
＆lt; div id =“facebook”＆gt;＆lt; img src =“http：/  /examepl.com/fb.png"></div>
＆lt; div id =“twiiter”＆gt;＆lt; img src =“http://examepl.com/t.png”＆gt;＆lt;  / div＆gt; 
＆lt; div id =“gplus”＆gt;＆lt; img src =“http://examepl.com/gp.png”＆gt;＆lt; / div＆gt; 
＆lt; / div＆gt; 
＆lt;  ; /报头＆GT;  
＆lt; div class =“container”＆gt; 
＆lt; p＆gt; SOme Post＆lt; / p＆gt; 
＆lt; img src =“http://examepl.com/some.png”title =“some image”  /＆gt; 
 
＆lt; p＆gt; SOme发布＆lt; / p＆gt; 
＆lt; img src =“http://examepl.com/some.png”title =“some image”/＆gt; 
 
  ＆lt; p＆gt; SOme Post＆lt; / p＆gt; 
＆lt; img src =“http://examepl.com/some.png”title =“some image”/＆gt; 
＆lt; / div＆gt; 
＆lt; 页脚＆gt; 
＆lt; div id =“foot”＆gt; 
 copyright and amp; copy;  2013 
＆lt; / div＆gt; 
＆lt; / footer＆gt; 
＆lt; / body＆gt; 
＆lt; / html＆gt; 
  code>  pre> 
 
 
我正在尝试 仅使用preg_match_all从我的image.php文件中获取图像，但它返回boolean（false）:(  p> 
 
 


我的php代码： -   p> 
 
 


 ＆lt;？php 
 $ file = file_get_contents（“image.php”）; 
preg_match_all（“/＆lt; div class = \”container \“＆gt;（。*？）＆lt; / div＆gt; /”，$  file，$ match）; 
preg_match_all（“/＆lt; img src = \”（。*？）\“＆gt; /”，$ match，$ images）; 
 
var_dump（$ images）; 
？＆gt;  ; 
  code>  pre> 
 
 
这两个文件都在根文件夹中，现在我得到空白页面：（ p> 
 
 


任何帮助都是 很好 p> 
 
 


谢谢 p> 
  div>

答

You can easily obtain what you want with an XPath query:

$url = 'http://examepl.com/image.php';

$doc = new DOMDocument();
@$doc->loadHTMLFile($url);
$xpath = new DOMXPath($doc);
$srcs = $xpath->query("//div[@class='container']//img/attribute::src");
foreach ($srcs as $src) {
    echo '<br/>' . $src->value; 
}

答 

preg_match_all("/<img src=\"(.*?)\">/", $match, $images);

replace with

preg_match_all("/<img src=\"(.*?)\"/", $match, $images); // stripped ">" char

答

You better not use regex for this purpose. PHP provides nice DOM api for this purpose. Consider code like below:

$html = <<< EOF
<div class="container">
<p>SOme Post</p>
<img src="http://examepl.com/some1.png" title="some image" />
<p>SOme Post</p>
<img src="http://examepl.com/some2.png" title="some image" />
<p>SOme Post</p>
<img src="http://examepl.com/some3.png" title="some image" />
</div>
EOF;
$doc = new DOMDocument();
libxml_use_internal_errors(true);
$doc->loadHTML($html); // loads your html
$xpath = new DOMXPath($doc);
$nodelist = $xpath->query("//div[@class='container']/img");
$img = array();
for($i=0; $i < $nodelist->length; $i++) {
    $node = $nodelist->item($i);
    $img[] = $node->getAttribute('src');
}
print_r($img);

OUTPUT:

Array
(
    [0] => http://examepl.com/some1.png
    [1] => http://examepl.com/some2.png
    [2] => http://examepl.com/some3.png
)

Live Demo: http://ideone.com/iBhVMF

答

I think this will work for you try the link below to test your regex

preg_match_all("/<div class=\"container\">(.*?)<\/div>/", $file, $match);
preg_match_all("/<img .*?(?=src)src=\"([^\"]+)\"/", $match[1][0], $images);

http://www.phpliveregex.com

相关推荐