Php：将可变金额天添加到Y-m-d日期格式

问题描述：

i'm trying to add days to a date with the 'Y-m-d' format:

$oldDate = '2013-05-15';
$newDate = date('Y-m-d', strtotime($oldDate. " + 5 days"));

This ouputs '2013-5-20', but below:

$oldDate = '2013-05-15';
$addedDays = 5;
$newDate = date('Y-m-d', strtotime($oldDate. " + $addedDays days"));

doesn't work, it only outputs '1970-01-01', which doesn't make sense because i only tried to put the days to be added in a variable. They're basically the same code. I appreciate the help trying to understand this. Thanks!

我正在尝试使用'Ymd'格式添加日期： p> \ n

  $ oldDate ='2013-05-15'; 
 $ newDate = date（'Ym-d'，strtotime（$ oldDate。“+ 5 days”））; 
  code>   pre> 
 
 此输出'2013-5-20'，但低于： p> 
 
 
  $ oldDate ='2013-05-15'; \  n $ addedDays = 5; 
 $ newDate = date（'Ym-d'，strtotime（$ oldDate。“+ $ addedDays days”））; 
  code>  pre> 
 
  不起作用，它只输出'1970-01-01'，这没有意义，因为我只试图将日期添加到变量中。 它们基本上是相同的代码。 我很感激帮助我们理解这一点。 谢谢！   p> 
  div>

答

However the code is right and works, just in case try

$newDate = date('Y-m-d', strtotime($oldDate. " + {$addedDays} days"));

答

Use the DateTime class. It will spare you a lot of head-ache.

// Create a DateTime object
$date = new DateTime('2013-05-15');

// Original date
echo $date->format('d. F Y'), '<br>';

// Add 5 days
$date->modify('+5 days');

// Modified date
echo $date->format('d. F Y'), '<br>';

答

I had checked it, but it doesn't work on my computer (likely due to the PHP version). I found an alternative solution, though:

$timeBase = time();

$sDays2change = '+182'; // 6 months

$newtime = strtotime($sDays2change . ' day', $timeBase);

echo date('d/m/Y', $newtime);

Php：将可变金额天添加到Y-m-d日期格式

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