在php中用于显示菜单的功能
I met some trouble with a function I have written.
In fact I have an array in which I have different custom values.
I would like to display the result of that, so here is my function
function getAccess($var){
$data=mysql_fetch_array(mysql_query("SELECT * FROM `acces` WHERE `id`='.$var.'"));
return $data;
}
getAccess($_SESSION['id']);
$paramAcces = array(
'comptesfinanciers' => array(
'libelle' => 'COMPTES FINANCIERS',
'acces' => $data['comptesfinanciers'],
'lien' => 'financier',
'image' => 'images/finances.png'
)
);
I have done a var_dump of $paramAcces which return
array(1) { ["comptesfinanciers"]=> array(4) { ["libelle"]=> string(18) "COMPTES FINANCIERS" ["acces"]=> NULL ["lien"]=> string(9) "financier" ["image"]=> string(19) "images/finances.png" } } (that are the ecpected values).
Here is the function for displaying what is in the array
/**
* AFFICHAGE DE LA SECTION PARAMETRES SUR LA PAGE D'ACCUEIL
*/
function affichParam($paramAccees){
echo '<ul class="getcash-vmenu"><li><a href="index.php?p='.$paramAccees['lien'].'" class="active"><span class="t"><img src="'.$paramAccees['image'].'"> '.$paramAccees['libelle'].'</span></a></li></ul>';
}
The trouble is that actualy it return to me an empty line.
I really do not know what I'm wrong doin:
I call the function like that:
<?php
affichParam($paramAccees)
?>
In a second time I will add more value, so I think I will have to do a for each loop or something like that.
But actualy I just would like to display the first record.
Any kind of help will be much apprecitaed
我遇到了一个我写过的函数的麻烦。 p>
实际上 我有一个数组,其中我有不同的自定义值。 p>
我想显示结果,所以这是我的函数 p>
function getAccess($ var){ $ data = mysql_fetch_array(mysql_query(“SELECT * FROM`access` WHERE`id` ='。$ var。'”)); 返回$ data; } NetAccess($ _ SESSION ['id']); $ paramAcces = array( 'comptesfinanciers'=&gt; array( 'libelle'=&gt;'COMPTES FINANCIERS', 'acces'=&gt; $ data ['comptesfinanciers'], 'lien'=&gt;'financier', 'image'=&gt;'images / finances.png' )\ n); code> pre>我做了一个$ paramAcces的var_dump,它返回 p>
array(1){[ “comptesfinanciers”] =&GT; array(4){[“libelle”] =&gt; string(18)“COMPTES FINANCIERS”[“acces”] =&gt; NULL [“lien”] =&gt; string(9)“financier”[“image”] =&gt; string(19)“images / finances.png”}}(这是预期的值)。 code> pre>
这是用于显示数组中的内容的函数
/ ** * AFFICHAGE DE LA SECTION PARAMETRES SUR LA PAGE D'ACCUEIL * / 函数affichParam($ paramAccees){ echo'&lt ; ul class =“getcash-vmenu”&gt;&lt; li&gt;&lt; a href =“index.php?p ='。$ paramAccees ['lien']。'”class =“active”&gt;&lt; span class =“t”&gt;&lt; img src =“'。$ paramAccees ['image']。'”&gt; '。$ paramAccees ['libelle']。'&lt; / span&gt;&lt; / a&gt;&lt; / li&gt;&lt; / ul&gt;'; } code> pre>
麻烦的是,它实际上给我一个空行。 p>
我真的不知道我错了什么: p>
我调用这样的函数: p>
&lt;?php affichParam($ paramAccees) ?&gt; code> pre>
第二次我将添加更多的值,所以我想我必须为每个循环或类似的东西做一个。 p>
但实际上,我只是希望显示第一条记录。 p>
任何形式的帮助都会得到很多赞赏 p> DIV>
lien
is apart of the comptesfinanciers
array which is apart of the paramAccees
array, which should be reflected as so:
echo '<ul class="getcash-vmenu"><li><a href="index.php?p='.$paramAccees['comptesfinanciers']['lien'].'" class="active"><span class="t"><img src="'.$paramAccees['comptesfinanciers']['image'].'"> '.$paramAccees['comptesfinanciers']['libelle'].'</span></a></li></ul>';