无法看到从Android设备上传的3gp文件到PHP Server
问题描述：
In my android code, I am trying to upload a .3gp file to XAMPP server. I reused the following code for uploading the file:
public int uploadFile(String sourceFileUri) {
String fileName = sourceFileUri;
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "
";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File(sourceFileUri);
if (!sourceFile.isFile()) {
dialog.dismiss();
Log.e("uploadFile", "Source File not exist :"
+uploadFilePath + "" + uploadFileName);
runOnUiThread(new Runnable() {
public void run() {
Toast.makeText(getApplicationContext(), "Source File not exist :"
+uploadFilePath + "" + uploadFileName, Toast.LENGTH_LONG).show();
}
});
return 0;
} else {
try {
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("uploaded_file", fileName);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
if(serverResponseCode == 200){
runOnUiThread(new Runnable() {
public void run() {
String msg = "File Upload Completed.
See uploaded file here :
"
+" http://www.androidexample.com/media/uploads/" +uploadFileName;
Toast.makeText(getApplicationContext(), "File Upload Complete.",
Toast.LENGTH_SHORT).show();
}
});
}
//close the streams //
fileInputStream.close();
dos.flush();
dos.close();
} catch (MalformedURLException ex) {
dialog.dismiss();
ex.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
Toast.makeText(getApplicationContext(), "MalformedURLException",
Toast.LENGTH_SHORT).show();
}
});
Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
} catch (Exception e) {
dialog.dismiss();
e.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
Toast.makeText(getApplicationContext(), "Got Exception : see logcat ",
Toast.LENGTH_SHORT).show();
}
});
Log.e("Upload file to server Exception", "Exception : "
+ e.getMessage(), e);
}
dialog.dismiss();
return serverResponseCode;
} // End else block
}
With the following parameters:
String upLoadServerUri = "http://"+iPAddress+"/patient/upload.php";
/********** File Path *************/
final String uploadFilePath = Environment.getExternalStorageDirectory().getPath()+"/Patient_Records/";
final String uploadFileName = "record.3gp";
below is my upload.php file:
<?php
$file_path = "uploads/";
$file_path = $file_path . basename( $_FILES['uploaded_file']['name']);
if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $file_path)) {
echo "success";
} else{
echo "fail";
}
?>
I do have a directory uploads in the same directory of upload.php, more specifically:
The PHP file upload.php full path is: C:\xampp\htdocs\patient\upload.php
The upload directory full path is: C:\xampp\htdocs\patient\uploads
The android activity does not complain. During runtime, I get the message "File Upload Complete." as if everything went well. However, I do NOT find the uploaded file in the upload directory. What's wrong?
答
I would recommend you using HttpClient class to send data in the form of multi-part. There's a simple solution mentioned here Video file transfer from Android phone to server (https://stackoverflow.com/a/17673687/2482430) which can be useful for you
Code
public void uploadVideo(Context context, String videoPath) {
try {
HttpClient httpClient = new DefaultHttpClient();
HttpPost postRequest = new HttpPost(context.getString(R.string.url_service_fbpost));
MultipartEntity reqEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
if(!videoPath.isEmpty()){
FileBody filebodyVideo = new FileBody(new File(videoPath));
reqEntity.addPart("uploaded", filebodyVideo);
}
postRequest.setEntity(reqEntity);
HttpResponse response = httpClient.execute(postRequest);
BufferedReader reader = new BufferedReader(new InputStreamReader(
response.getEntity().getContent(), "UTF-8"));
String sResponse;
StringBuilder s = new StringBuilder();
while ((sResponse = reader.readLine()) != null) {
s = s.append(sResponse);
}
Log.e("Response: ", s.toString());
return true;
} catch (Exception e) {
Log.e(e.getClass().getName(), e.getMessage());
return false;
}
}