在PHP开关中使用比较运算符

问题描述：

So I have four conditions that I need to go through and I thought it would be best to use the switch statement in PHP. However, I need to check whether an integer is, let's say, less than or equal, or greater than and equal.

switch ($count) {
    case 20:
        $priority = 'low';
        break;

    case 40:
        $priority = 'medium';
        break;

    case 60:
        $priority = 'high';
        break;

    case 80:
        $priority = 'severe';
        break;
}

With an if() statement it would look like the following:

if ($count <= 20) {
    $priority = 'low';
}

if ($count <= 40) {
    $priority = 'medium';
}

Is that possible in switch-case?

答

A more general case for solving this problem is:

switch (true) {
    case $count <= 20:
        $priority = 'low';
        break;

    case $count <= 40:
        $priority = 'medium';
        break;

    case $count <= 60:
        $priority = 'high';
        break;

    default:
        $priority = 'severe';
        break;
}

答

No. switch() statements are for doing multiple equality tests. They're basically just a slightly easier to read (but also more hazardous) version of

if (x == 'a') { ... }
else if (x == 'b') { ... } 
else if (x == 'c') { ... }

code. There is no way to change a switch() away from == to < or any other comparison operator. It's strictly for equality testing.

答

Switches can't do that, but in this particular case you can do something like this:

switch ((int)(($count - 1) / 20)) {
    case 0:
        $priority = 'low';
        break;
    case 1:
        $priority = 'medium';
        break;
    case 2:
        $priority = 'high';
        break;
    case 3:
        $priority = 'severe';
        break;
}

So in (int)(($count - 1) / 20) all values from 0 to 20 will eval to 0, 21 to 40 will eval to 1 and so on, allowing you to use the switch statement for this purpose.

And since we are concatenating values, we can even simplify to an array:

$priorities = ['low', 'medium', 'high', 'severe'];
$priority = $priorities[(int)(($count - 1) / 20)];

答

There is a way that works in php 7 using ternary assignment operators. The operator was introduced earlier on (5.4?) but I never tested the code on other versions. I wrote the whole switch code there, however for brevity here is just the specific clause. Let's say we want the condition to match for all numbers greater than or equal to five :

switch($value){
 case ($value >= 5?$value:!$value)://do something here
 break;
}

We either allow the $value to pass unchanged or we negate the value according to the condition. A $value will always match itself or fail the test against its negation.

答

I can also confirm @bytepunk answer here is functional.

Also, expending the concept with PHP 7

switch ($interval->days)
{
    case 0:
        return '1 day';
        // break;
    case (($interval->days >= 1 && $interval->days <= 7) ?? $interval->days):
        return '1 week';
        // break;
    case (($interval->days >= 8 && $interval->days <= 31) ?? $interval->days):
        return '1 month';
        // break;
    case (($interval->days >= 31 && $interval->days <= 93) ?? $interval->days):
        return '2-3 months';
        // break;
    default:
        return '3+ months';
}

I will admit that this isn't the cleanest of code, so perhaps wrapping each case with a static-like pure function would neat things up a bit, and not forgetting to name each function (or create one generic function with parameters) to match the case. This will make it more readable.

在PHP开关中使用比较运算符

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