从x可编辑的php中获取选择选项

问题描述：

I am using x editable for inline editing.

JQUERY

$('#status').editable({
  value: 2,
  source: [
  {value: 1, text: 'Active'},
  {value: 2, text: 'Blocked'},
  {value: 3, text: 'Deleted'}
  ]
});

This one is running fine. But the problem is, I want to get source options from php. For that I have an array.

PHP

$php_array = Array ( [MOBILE_TOPUP] => MOBILE_TOPUP
                     [PICKUP] =>PICKUP
                     [DELIVERY] => DELIVERY
                     [BANK_DEPOSIT] => BANK_DEPOSIT )

I tried with by passing below variable in source but it's not working:

var json_array = <?=json_encode($php_array)?>;

How can I achieve this? Do I need to change array structure in PHP? Thanks for any help!

我正在使用x editable进行内联编辑。 p>

JQUERY strong> p>

  $（'＃status'）。editable（{
 value：2，
 source：[
 {value：1，text：' 有效'}，
 {值：2，文字：'已屏蔽'}，
 {值：3，文字：'已删除'} 
 
 
} 
}）; 
  code>  pre> \  n 
 这个运行正常。 但问题是，我想从 php  code>获取源选项。 为此我有一个数组。 p> 
 
 
  PHP  strong>  p> 
 
 
  $ php_array = Array（[MOBILE_TOPUP] =＆gt  ; MOBILE_TOPUP 
 [PICKUP] =＆gt; PICKUP 
 [DELIVERY] =＆gt; DELIVERY 
 [BANK_DEPOSIT] =＆gt; BANK_DEPOSIT）
  code>  pre> 
 
 我试过 通过在源中传递下面的变量，但它不起作用： p> 
 
 
  var json_array =＆lt;？= json_encode（$ php_array）？＆gt ;; 
  code>  pre  > 
 
 我如何实现这一目标？ 我是否需要在 PHP  code>中更改数组结构？ 谢谢你的帮助！ p> 
  div>

答

Yes, you have to change array structure as below :

$php_array = Array ( 
        array('value' => 1, 'text' => 'Active'),
        array('value' => 2, 'text' => 'Blocked'),
        array('value' => 3, 'text' => 'Deleted'),
);

var json_array = '<?=json_encode($php_array)?>';

答

You shouldn't use PHP inside JS, better to make an ajax call. This feature is built into x-editable if you use the source option with a string like so:

$('#status').editable({
  value: 2,
  source: 'mypage.php'
});

从x可编辑的php中获取选择选项

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