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Sed更换令牌的问题

分类: 技术问答 • 2022-04-08 19:10:00
问题描述：

I have a bit of bash that I use to "install" a wordpress site on a server.

In it, I do a curl request to get the randomized SALTs via SALTS=$(curl -L https://api.wordpress.org/secret-key/1.1/salt/);

And I put a "token" in my wp-config.php file ##WP_SALTS##

It seems that my sed statement is not proper, as it keeps throwing me an error:

sed: -e expression #1, char 99: unknown option to `s'

I have tried:

sed -i "s+##WP_SALTS##+$SALTS+g" $WPCONFIG

As well: 

sed -i "s/##WP_SALTS##/$SALTS/g" $WPCONFIG

Still the error presents. What am I doing wrong?

the response from the curl request are random each time, but are similar to:

define('AUTH_KEY', ':a>?5od_kaveFKaIB8px|!vgF-W/6/AQX04=&>Tu.-q3ehGOh59=SX+qc9sWk|gG'); define('SECURE_AUTH_KEY', ':tw+w! Sn2n~Rt0ReVA6#eWqsUXW5elHo@V~ oiRhTH4k]kg{<k`:An`]z==K@wZ'); define('LOGGED_IN_KEY', 'mD,JT*4pa3}zfGEpXFR}9jlzF,iD ;:]|>yu]T}&8Uy~(-5ml/AEBTG4|7QYCB|j'); define('NONCE_KEY', '@{Q`.7T a)S?0DTutE}D5Is(UlwnG4NuoQiFHas&i@qz%-HTd7-8[v50Nx<]akuT'); define('AUTH_SALT', 'es*7hCVnh/+c-cecgmZ?%QZ_KN^kaA[jD]N}{A8sK|~MH@Vl|(6-|{3EIGMhksy['); define('SECURE_AUTH_SALT', '}AF@:i!hy#C5,Q_5c4yhycm~i|fc53@+|h7r5H9y(/&4VBeX&sOrKC-6+AqeZ|L>'); define('LOGGED_IN_SALT', '4,}H+&[@qN#^!B+?3a+Mh0+?pURhP|v.CV/]4F-6G!TncU*Pd=GMSRPf?58j5Sv0'); define('NONCE_SALT', 'Dlo,7F[:EaWQT57-P0Q+x</nUf4UD&LH=-0wS6l._2Fx!-jR0KBJ-U_1*{sXo?>Q');

EDIT Now implementing a way to randomly generate the 64 character salts with the following:

RSTR=$(cat /dev/urandom | tr -dc 'a-zA-Z0-9' | fold -w ${1:-64} | head -n 1);
SALTS="define('AUTH_KEY', '$RSTR');
define('SECURE_AUTH_KEY', '$RSTR');
define('LOGGED_IN_KEY', '$RSTR');
define('NONCE_KEY', '$RSTR');
define('AUTH_SALT', '$RSTR');
define('SECURE_AUTH_SALT', '$RSTR');
define('LOGGED_IN_SALT', '$RSTR');
define('NONCE_SALT', '$RSTR');";
sed -i "s/##WP_SALTS##/$SALTS/g" $WPCONFIG

I've replaced the delimiter with +, ~, /, &, * and they all still generate this same error.

我有一些bash用于在服务器上“安装”wordpress网站。 p>

在其中，我通过 SALTS = $（curl -L https://api.wordpress.org/secret-key/1.1/salt/）进行卷曲请求以获取随机化的SALT ; code> p>

我在wp-config.php文件中加了一个“令牌” ## WP_SALTS ## code> p> \ n

似乎我的 sed code>语句不正确，因为它不断给我一个错误： p> 

  sed：-e expression＃1  ，char 99：未知选项`s'
  code>  pre> 
 
 
我尝试过： p> 
 
 


  sed -i“s +  ## WP_SALTS ## + $ SALTS + g“$ WPCONFIG 
  code>  pre> 
 
 
同样： p> 
 
 


  sed -i  “s / ## WP_SALTS ## / $ SALTS / g”$ WPCONFIG 
  code>  pre> 
 
 
仍然出现错误。 我做错了什么？ p> 
 
 


  curl  code>请求的响应每次都是随机的，但类似于： p> 
 
 
  define（'AUTH_KEY'，'：a＆gt;？5od_kaveFKaIB8px |！vgF-W / 6 / AQX04 =＆amp;＆gt; Tu.-q3ehGOh59 = SX + qc9sWk | gG'）;  define（'SECURE_AUTH_KEY'，'：tw + w！Sn2n~Rt0ReVA6＃eWqsUXW5elHo @ V~oiRhTH4k] kg {＆lt; k`：An`] z == K @ wZ'）;  define（'LOGGED_IN_KEY'，'mD，JT * 4pa3} zfGEpXFR} 9jlzF，iD;：] |＆gt; yu] T}＆amp; 8Uy~（-5ml / AEBTG4 | 7QYCB | j'）; define（'NONCE_KEY'，  '@ {Q`.7T a）S？0DTutE} D5Is（UlwnG4NuoQiFHas＆amp; i @ qz％-HTd7-8 [v50Nx＆lt;] akuT'）; define（'AUTH_SALT'，'es * 7hCVnh / + c-cecgmZ？％  QZ_KN ^ kaA [jD] N} {A8sK | ~MH @ Vl |（6- | {3EIGMhksy ['）; define（'SECURE_AUTH_SALT'，'} AF @：i！hy＃C5，Q_5c4yhycm~i | fc53 @ +  | h7r5H9y（/＆amp; 4VBeX＆amp; sOrKC-6 + AqeZ | L＆gt;'）;定义（'LOGGED_IN_SALT'，'4，} H +＆amp; [@ qN＃^！B +？3a + Mh0 +？pURhP | v.CV  ！/] 4F-6G TncU * PD = GMSRPf 58j5Sv0 '）;定义（' NONCE_SALT '' DLO，7F [：？！EaWQT57-P0Q + X＆LT; / nUf4UD＆安培; LH = -0wS6l._2Fx -jR0KBJ-U_1 * {  sXo？＆gt; Q'）; 
  code>  pre> 
 
 
 编辑 strong> 
现在实现一种随机生成64个字符盐的方法： 
 
 
  RSTR = $（cat / dev / urandom | tr -dc'a-zA-Z0-9'| fold -w $ {1：-64} | head -n  1）; 
SALTS =“define（'AUTH_KEY'，'$ RSTR'）; 
define（'SECURE_AUTH_KEY'，'$ RSTR'）; 
define（'LOGGED_IN_KEY'，'$ RSTR'）; 
define（'NONCE_KEY  '，'$ RSTR'）; 
define（'AUTH_SALT'，'$ RSTR'）; 
define（'SEC  URE_AUTH_SALT'，'$ RSTR'）; 
define（'LOGGED_IN_SALT'，'$ RSTR'）; 
define（'NONCE_SALT'，'$ RSTR'）;“; 
sed -i”s / ## WP_SALTS ## /  $ SALTS / g“$ WPCONFIG 
  code>  pre> 
 
 
我用+，〜，/，＆amp;，*替换了分隔符，它们仍然会产生同样的错误。   p> 
  div>

答

If SALTS may contain any character it can be done with perl.

Passing by environment :

SALTS="$SALTS" perl -i.bak -pe 's/##WP_SALTS##/$ENV{SALTS}/g' "$WPCONFIG"

Passing by arguments :

perl -i.bak -pe 'BEGIN{$salts=shift}s/##WP_SALTS##/$salts/g' "$SALTS" "$WPCONFIG"

答

$SALTS may contain the character used as delimiter (+ or /). If your file doesn't contain ~ you could try:

sed -i "s~##WP_SALTS##~$SALTS~g" $WPCONFIG

But you can use any printable character as delimiter.

With GNU sed, you can also choose a non-printable one (see "sed rare-delimiter (other than & | / ?…)".

答

When you need a literal string, don't use sed as it only understands regexps and replacement strings with backreferences and has delimiter constraints. Just use a tool with string functions like awk:

SALTS="$SALTS" awk -i inplace '
BEGIN { old="##WP_SALTS##""; lgth=length(old); new=ENVIRON["SALTS"] }
s=index($0,old) { $0=substr($0,1,s-1) new substr($0,s+lgth) }
{ print }
' "$WPCONFIG"

The above uses GNU awk for inplace editing with -i inplace, just like your GNU sed was doing with -i.

Don't use all upper case variable names for non-exported variables btw - that's by convention and to avoid clashes with exported and builtin variables.

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