如何在保留索引名称的同时在php中合并数组递归
问题描述：
I've been searching and haven't found an answer yet to my question.
Say I want to create a menu out of three or more arrays, but I don't what elements will those arrays have.
I have something like this:
$arr1 = array(
'design' => 'Link 1'
);
$arr2 = array(
'development' => 'Link 2'
);
$arr3 = array(
'design' => 'Link 3',
'seo' => 'Link 4'
);
What can I do to turn those three arrays into this:
$final_array = array(
'development' => 'Link 2',
'seo' => 'Link 4',
'design' => array(
'0' => 'Link 1',
'1' => 'Link 3'
),
);
我一直在搜索，但尚未找到答案。 p> \ n
假设我想用三个或更多数组创建一个菜单，但我不知道那些数组会有哪些元素。 p>
我有这样的东西： p >
$ arr1 = array（
'design'=＆gt;'Link 1'
）;
$ arr2 = array（
'development'=＆gt;' 链接2'
）;
$ arr3 =数组（
'设计'=＆gt;'链接3'，
'seo'=＆gt;'链接4'
）;
code > pre>
如何将这三个数组转换为： p>
$ final_array = array（
'development'=＆gt; ;'链接2'，
'seo'=＆gt;'链接4'，
'设计'=＆gt;数组（
'0'=＆gt;'链接1'，
'1'=＆gt; 'Link 3'
），
）;
code> pre>
div>
答
$arr1 = array(
'design' => 'Link 1'
);
$arr2 = array(
'development' => 'Link 2'
);
$arr3 = array(
'design' => 'Link 3',
'seo' => 'Link 4'
);
$newarr = array_merge_recursive($arr1, $arr2, $arr3);
print_r($newarr);