Angularjs和jquery不能以我的常规简单形式工作

问题描述：

I am learning Angularjs and I created simple form. Actually i am PHP developer so i preferred to use php as a server side scripting language. I am unable to submit the data to server, i tried so many methods but those are very complex if i am trying in standard method Angularjs is not working please check my code, and give me best method to work with angularjs, jquery and php. help me!

angular.module("mainModule", [])
  .controller("mainController", function($scope, $http) {
    $scope.person = {};
    $scope.serverResponse = '';

    $scope.submitData = function() {
      var config = {
        headers: {
          "Content-Type": "application/x-www-form-urlencoded"
        }
      };

      $http.post("server.php", $scope.person, config)
        .success(function(data, status, headers, config) {
          $scope.serverResponse = data;
        })
        .error(function(data, status, headers, config) {
          $scope.serverResponse = "SUBMIT ERROR";
        });
    };
  });

<?php
 if (isset($_POST["person"]))
  {
    // AJAX form submission
    $person = json_decode($_GET["person"]);

    $result = json_encode(array(
      "receivedName" => $person->name,
      "receivedEmail" => $person->email));
  }  else
  {
    $result = "INVALID REQUEST DATA";
  }

  echo $result;

?>

<!DOCTYPE html>
<html>

<head>
</head>

<body ng-app="mainModule">
  <div ng-controller="mainController">
    <form name="personForm1" novalidate ng-submit="submitData()">
      <label for="name">First name:</label>
      <input id="name" type="text" name="name" ng-model="person.name" required />
      <br />
      {{person.name}}
      <br />
      <label for="email">email:</label>
      <input id="email" type="text" name="email" ng-model="person.email" data-parsley-type="email" required />
      <br />
      <br />
      <button type="submit">Submit</button>
    </form>
    <br />
    <div>
      {{$scope.serverResponse}}
    </div>
  </div>

  <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
  <script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
  <!--<script type="text/javascript" src="script/parsley.js"></script>
  <script src="script.js"></script>-->
</body>

</html>

</div>

答

Updated, this is code that was just tested with php and Apache - and it works. I also changed your server.php file like below. The file was created based on AngularJS Hub's Server Calls sample. The same source was used to create mainController.js' $http.post(...) method call so that it successfully posts data to the server.

Screenshot (after submit)

enter image description here

server.php

<?php
 if ($_SERVER["REQUEST_METHOD"] === "POST")
  {

   $result = "POST request received!";

  if (isset($_GET["name"]))
  {
    $result .= "
name = " . $_GET["name"];
  }

  if (isset($_GET["email"]))
  {
    $result .= "
email = " . $_GET["email"];
  }

  if (isset($HTTP_RAW_POST_DATA))
  {
    $result .= "
POST DATA: " . $HTTP_RAW_POST_DATA;
  }

  echo $result;
  }

?>

personForm.html

   <!DOCTYPE html>
    <html lang="en" xmlns="http://www.w3.org/1999/xhtml">
    <head>
        <meta charset="utf-8" />
        <title></title>

    </head>
        <body ng-app="mainModule">
            <div ng-controller="mainController">
                <form name="personForm1" validate ng-submit="submit()">
                    <label for="name">First name:</label>
                    <input id="name" type="text" name="name" ng-model="person.name" required />
                    <br />
                    {{person.name}}
                    <br />
                    <label for="email">email:</label>
                    <input id="email" type="text" name="email" ng-model="person.email" required />
                    <br />
                    <br />
                    <button type="submit">Submit</button>
                </form>
                <br />
                <div>
                    {{serverResponse}}
                </div>
            </div>

            <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
            <script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.3.11/angular.min.js"></script>
            <script src="mainController.js"></script>
            <!--<script type="text/javascript" src="script/parsley.js"></script>
            <script src="script.js"></script>-->
        </body>

</html>

mainController.js

angular.module("mainModule", [])
  .controller("mainController", function ($scope, $http)
  {
  $scope.person = {};

  $scope.serverResponse = "";

  $scope.submit = function ()
  {

      console.log("form submit");

      var params = {
          name: $scope.person.name,
          email: $scope.person.email
      };

      var config = {
          params: params
      };

      $http.post("server.php", $scope.person, config)
      .success(function (data, status, headers, config)
      {
          console.log("data " + data + ", status "+ status + ", headers "+ headers + ", config " + config);
          $scope.serverResponse = data;
          console.log($scope.serverResponse);
      })
      .error(function (data, status, headers, config)
      { console.log("error");
          $scope.serverResponse = "SUBMIT ERROR";


       });
      };
  });// JavaScript source code

Alternative way, with JSON handling:

server_json.php

<?php
  if ($_SERVER["REQUEST_METHOD"] === "POST")
  {
     /* code source: http://stackoverflow.com/a/22852178/2048391 */
     $data = array();
     $json = file_get_contents('php://input'); // read JSON from raw POST data

     if (!empty($json)) {
        $data = json_decode($json, true); // decode
     }

     print_r($data);

    }

  ?>

Screenshot (after submit)

Screenshot

答

You're using angular form and posting data from controller internally then you should not suppose to be mention action="server.php" method="post" because you are going to do this call from controller i.e. $http.post('server.php').

Just add ng-submit="submitData(person, 'result')" directive in your form tag, that will call your controller method which is posting data and your code will start working.

HTML

<form name="personForm1" novalidate ng-submit="submitData(person, 'result')">
    <label for="name">First name:</label>
    <input id="name" type="text" name="name" ng-model="person.name" required />
    <br />{{person.name'}}
    <label for="email">Last name:</label>
    <input id="email" type="text" name="email" ng-model="person.email" data-parsley-type="email" required />
    <br />
    <br />
    <button type="submit">Submit</button>
</form>

Hope this could help you. Thanks.

答

It seems from your code that you misunderstood some concepts.

You're not using jQuery at all - you can remove it unless parsely (not familiar with this one...) requires it
All HTML tags besides the DOCTYPE should be inside the root html tag. It's recommended to add JS at the bottom of the body tag which will (conceptually) contribute to page load performance.
The order of JS you import is important and should be by dependencies (eg: AngularJS can uses jQuery only if it's included but in your case angular doesn't know about it since the jQuery is added after AngularJS which causes Angular to build its jq lite instead)
You added a submitData to your controller's scope but you never call it - your intention was probably to use it when the user submits the form so you need to remove action and method attributes from the form and add ng-submit: <form name="personForm1" method="post" novalidate ng-submit="submitData(person, 'thePropNameOnWhichYouWantToSaveTheReturnedData')">. Both arguments are redundant since you have them on the $scope.
The config argument sent with $http service is used for configurations, not data. Read here: Angular $http
the default behavior of the $http is sending JSON as the request's body. It seems that you expect a form on your PHP code. This can be changed in the config for example, or you can learn how to deserialize JSONs on PHP (sorry, I don't know PHP).
Add the property on which you want to save the data to the $scope so it could be rendered.

Fixed client code suggestion:

angular.module("mainModule", [])
  .controller("mainController", function($scope, $http) {
    $scope.person = {};
    $scope.serverResponse = '';

    $scope.submitData = function() {
      // Let's say that your server doesn't expect JSONs but expects an old fashion submit - you can use the `config` to alter the request
      var config = {
        headers: {
          "Content-Type": "application/x-www-form-urlencoded"
        }
      };

      $http.post("server.php", $scope.person, config) // You can remove the `config` if the server expect a JSON object
        .success(function(data, status, headers, config) {
          $scope.serverResponse = data;
        })
        .error(function(data, status, headers, config) {
          $scope.serverResponse = "SUBMIT ERROR";
        });
    };
  });

<!DOCTYPE html>
<html>

<head>
</head>

<body ng-app="mainModule">
  <div ng-controller="mainController">
    <form name="personForm1" novalidate ng-submit="submitData()">
      <label for="name">First name:</label>
      <input id="name" type="text" name="name" ng-model="person.name" required />
      <br />
      {{person.name}}
      <br />
      <label for="email">email:</label>
      <input id="email" type="text" name="email" ng-model="person.email" data-parsley-type="email" required />
      <br />
      <br />
      <button type="submit">Submit</button>
    </form>
    <br />
    <div>
      {{$scope.serverResponse}}
    </div>
  </div>

  <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
  <script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
  <!--<script type="text/javascript" src="script/parsley.js"></script>
  <script src="script.js"></script>-->
</body>

</html>

You should also read some more on AngularJS docs and maybe do their full tutorial. It's extremely helpful

</div>

Angularjs和jquery不能以我的常规简单形式工作

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