如何使用PHP获取字符串中的html的特定属性？

问题描述：

I got a string and I need to find out all the data-id numbers. This is the string

<li data-type="mentionable" data-id="2">bla bla... 
<li data-type="mentionable" data-id="812">some test 
<li>bla bla </li>more text 
<li data-type="mentionable" data-id="282">

So in the end It will find me this : 2,812,282

我有一个字符串，我需要找出所有data-id code>数字。这是字符串 p>

 ＆lt; li data-type =“availableable”data-id =“2”＆gt; bla bla ... 
＆lt; li data-type  =“提及”data-id =“812”＆gt;某些测试
＆lt; li＆gt; bla bla＆lt; / li＆gt;更多文字
＆lt; li data-type =“提及”data-id =“282”＆gt; \  n  code>  pre> 
 
 所以最后它会找到我： 2,812,282  code>  p> 
  div>

答

You can use regex to find target part of string in preg_match_all().

preg_match_all("/data-id=\"(\d+)\"/", $str, $matches);
// $matches[1] is array contain target values
echo implode(',', $matches[1]) // return 2,812,282

See result of code in demo

Because your string is HTML, you can use DOMDocument class to parse HTML and find target attribute in document.

答

Use DOMDocument instead:

<?php

$data = <<<DATA
<li data-type="mentionable" data-id="2">bla bla... 
<li data-type="mentionable" data-id="812">some test 
<li>bla bla </li>more text 
<li data-type="mentionable" data-id="282">
DATA;

$doc = new DOMDocument();
$doc->loadHTML($data, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);

$xpath = new DOMXPath($doc);

$ids = [];
foreach ($xpath->query("//li[@data-id]") as $item) {
    $ids[] = $item->getAttribute('data-id');
}
print_r($ids);
?>

Which gives you 2, 812, 282, see a demo on ideone.com.

如何使用PHP获取字符串中的html的特定属性？

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