PHP在RSS提要中附加所有URL

问题描述：

I am trying to append all urls in a RSS feed with a extra string (like "/testing123" etc). The original url format from the RSS looks like this:

<link rel="alternate" type="text/html" href="http://website.com/item/name1/2162561"/>
<link rel="alternate" type="text/html" href="http://website.com/item/name2/2162435"/>

etc, I used regexp with str_replace in a for loop but i cannot seem to get it working correctly and if i use preg_replace i get errors. When i just echo out the urls with the string appended it appears how i want but when i use str_replace then the urls looks like this instead:

http://website.com/testing123/item/name1/2162561
http://website.com/testing123/item/name2/2162435

I need the urls with the append string at the end when they get replaced however like this:

<link rel="alternate" type="text/html" href="http://website.com/item/name1/2162561/testing123"/>
<link rel="alternate" type="text/html" href="http://website.com/item/name2/2162435/testing123"/>

The code i have is:

<?php 

// The append string
$append = '/testing123';

// The file
$file = "RSS.txt";

// Get the files contents
$contents = file_get_contents($file);

// The search pattern
$SearchPattern = '/href=["|\'](.[^"|\']+)/i';

// Run preg_match_all to grab all the Matches
preg_match_all( $SearchPattern, $contents, $Matches );

// Check to see if we have at least 1 match
$MatchCount = count($Matches[0]);

// If there is more than 1 match then run a for loop
if ( $MatchCount > 0 ) {
     for ( $i=0; $i < $MatchCount ; $i++ ) {

          $temp = $Matches[0][$i];
          echo $temp . $append . '<br />'; // Appears to work

          //$contents = str_replace($temp, $temp . $append, $contents); // But str_replace doesn't seem to work

          //preg_replace($temp, $temp . $append, $contents); // And using preg_replace gives a error

     };
};

echo $contents; // Display the contents

?>

我试图将所有网址附加到带有额外字符串的RSS源中（例如“/ testing123”等）。来自RSS的原始url格式如下所示： p>

 ＆lt; link rel =“alternate”type =“text / html”href =“http://website.com  / item / name1 / 2162561“/＆gt; 
＆lt; link rel =”alternate“type =”text / html“href =”http://website.com/item/name2/2162435“/＆gt; 
  代码>  pre> 
 
 等，我在for循环中使用了带有str_replace的regexp，但我似乎无法使其正常工作，如果我使用preg_replace，我会收到错误。 当我只是用附加的字符串回显url时，它显示我想要的但当我使用str_replace时，url看起来像这样： p> 
 
 
  http://website.com  /testing123/item/name1/2162561
http://website.com/testing123/item/name2/2162435

nn我需要带有追加字符串的网址 当它们被替换时结束，如下所示： p> 
 
 
 ＆lt; link rel =“alternate”type =“text / html”href =“http://website.com/  item / name1 / 2162561 / testing123“/＆gt; 
＆lt; link rel =”alternate“type =”text / html“href =”http://website.com/item/name2/2162435/testing123“/＆gt; \  n  code>  pre> 
 
 我的代码是： p> 
 
 
 ＆lt;？php 
 
 //追加字符串\  n $ append ='/ testing123'; 
 
 //文件
 $ file =“RSS.txt”; 
 
 //获取文件内容
 $ contents = file_get_contents（$ file）; \  n 
 //搜索模式
 $ SearchPattern ='/ href=["|\'（（。[^] ||'] +）/ i'; 
nn运行preg_match_all以获取所有 Matches 
preg_match_all（$ SearchPattern，$ contents，$ Matches）; 
 
  //检查我们是否至少有1个匹配
 $ MatchCount = count（$ Matches [0]）; 
 
 //如果匹配次数超过1，则运行for循环
if（$ MatchCount＆gt  ;  0）{
 for（$ i = 0; $ i＆lt; $ MatchCount; $ i ++）{
 
 $ temp = $ Matches [0] [$ i]; 
 echo $ temp。  $ append。  '＆lt; br /＆gt;';  //似乎工作
 
 // $ contents = str_replace（$ temp，$ temp。$ append，$ contents）;  //但是str_replace似乎不起作用
 
 // preg_replace（$ temp，$ temp。$ append，$ contents）;  //并使用preg_replace给出错误
 
}; 
}; 
 
echo $ contents;  //显示内容
 
？＆gt; 
  code>  pre> 
  div>

答

This should work :

<?php 

// The append string
$append = '/testing123';

// The file
$file = "RSS.txt";

// Get the files contents
$contents = file_get_contents($file);

// The search pattern
$SearchPattern = '/(<link .* href=".*)("\/>)/i';

// Run preg_match_all to grab all the Matches
preg_match_all( $SearchPattern, $contents, $matches );

for($i=0;$i<count($matches[1]);$i++){
    echo $matches[1][$i].$append.$matches[2][$i]."
";
}

?>

Basically, it filters the lines with regular expressions and extracts both sides of the index where you want to append text.

It then concatenates it all.

答

you need another variable to hold an array of $temp.

$match[i] = $temp . $append;

then echo $match later (in a for loop or for each loop)

Or keep match as a string and append the
as well

// If there is more than 1 match then run a for loop

if ( $MatchCount > 0 ) {
     for ( $i=0; $i < $MatchCount ; $i++ ) {

          $temp = $Matches[0][$i];
          $match .= $temp . $append . '<br />'; // Appears to work

          //$contents = str_replace($temp, $temp . $append, $contents); // But str_replace doesn't seem to work

          //preg_replace($temp, $temp . $append, $contents); // And using preg_replace gives a error

     };
};

echo $match; // Display the contents

?>

答

Instead of preg matching/replacing, you could use XPath and DOMDocument

$html = <<< EOF
<xml>
  <items>
    <item>
      <link href="/testing/123" />
      <link href="http://test" />
      <font><tag>x</tag></font>
    </item>
  </items>
</xml>
EOF;

Example XML is absurd, of course. Code below checks for relative links, and makes them absolute.

$doc = new DOMDocument();
@$doc->loadXML( $html );
$xpath = new DOMXpath( $doc );

$links = $xpath->query( "//link" );
for( $i = 0; $i < $links->length; $i++ ) {
    $href = $links->item($i)->getAttribute( 'href' );
    if( substr($href, 0, 4) != 'http' ) { 
        $links->item($i)->setAttribute( 'href', "http://" . ltrim($href, '/') );
    }
}

echo $doc->saveHTML();

That spits out transformed HTML:

<xml>
<items>
<item>
<link href="http://testing/123">
<link href="http://test">
<font><tag>x</tag></font>
</item>
</items>
</xml>

PHP在RSS提要中附加所有URL

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