使用nsurlconnection请求php脚本

问题描述：

i try to send value to server with this code by i have an error on this line:

let reply = NSURLConnection.sendSynchronousRequest(request, returningResponse:&response, error: &error)

the error is : EXTRA ARGUMENT IN CALL "error"

var yourUrl="mylink"
let url = NSURL(string:yourUrl)
let cachePolicy = NSURLRequestCachePolicy.ReloadIgnoringLocalCacheData
var request = NSMutableURLRequest(URL: url!, cachePolicy: cachePolicy, timeoutInterval: 2.0)
request.HTTPMethod = "POST"

// set Content-Type in HTTP header
let boundaryConstant = "
V2ymHFg03esomerandomstuffhbqgZCaKO6jy";
let contentType = "multipart/form-data; boundary=" + boundaryConstant
NSURLProtocol.setProperty(contentType, forKey: "Content-Type", inRequest: request)

// set data

var dataString = "my value"

let requestBodyData = (dataString as NSString).dataUsingEncoding(NSUTF8StringEncoding)
request.HTTPBody = requestBodyData

var response: NSURLResponse? = nil
var error: NSError? = nil
let reply = NSURLConnection.sendSynchronousRequest(request, returningResponse:&response, error: &error)

let results = NSString(data:reply!, encoding:NSUTF8StringEncoding)

if let dataFromString = results!.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false) {

let json = JSON(data: dataFromString)


if(json=="0"){

print("
 Dati non validi");

}

else{

print("
 Account creato");
}
}

答

You should never use sendSynchronousRequest as it is a blocking call. Also it is deprecated from iOS 9.0 onwards. Instead you can use NSURLSession. Try out following code

var yourUrl="mylink"
let URL = NSURL(string:yourUrl)
let request:NSMutableURLRequest = NSMutableURLRequest(URL: URL)
let boundaryConstant = "V2ymHFg03esomerandomstuffhbqgZCaKO6jy";
let contentType = "multipart/form-data; boundary=" + boundaryConstant
NSURLProtocol.setProperty(contentType, forKey: "Content-Type", inRequest: request)
var dataString = "my value"
request.HTTPMethod = "POST"
request.HTTPBody = (dataString as NSString).dataUsingEncoding(NSUTF8StringEncoding)
let task = NSURLSession.sharedSession().dataTaskWithRequest(request, completionHandler: { (data, response, error) -> Void in
    //reponse recieved
    //in this case response string will be saved in data, its of type NSData
    do{
         let str = try NSJSONSerialization.JSONObjectWithData(data!, options: NSJSONReadingOptions.AllowFragments) as! [String:AnyObject]
         print(str)
    }
    catch {
         print("json error: \(error)")
    }
    })
task.resume()

使用nsurlconnection请求php脚本

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