php简单的html dom解析器不返回任何内容
问题描述：
Why won't my script return the div with the id of "pp-featured"?
<?php
# create and load the HTML
include('lib/simple_html_dom.php');
$html = new simple_html_dom();
$html->load("http://maps.google.com/maps/place?cid=6703996311168776503&q=hills+garage&hl=en&view=feature&mcsrc=google_reviews&num=20&start=0&ved=0CFUQtQU&sa=X&ei=sCq_Tr3mJZToygTOmuCGCg");
$ret = $html->find('div[id=pp-featured]');
# output it!
echo $ret->save();
?>
答
this gets me on my way. Thanks for your help.
<?php
include_once 'lib/simple_html_dom.php';
$url = "http://maps.google.com/maps/place?cid=6703996311168776503&q=hills+garage&hl=en&view=feature&mcsrc=google_reviews&num=20&start=0&ved=0CFUQtQU&sa=X&ei=sCq_Tr3mJZToygTOmuCGCg";
$html = file_get_html($url);
$ret = $html->find('div[id=pp-reviews]');
foreach($ret as $story)
echo $story;
?>
答
The library always returns an array because it may be possible that more than one item matches the selector.
If you expect only one you should check to ensure the page your analyzing is behaving as expected.
Suggested solution:
<?php
include_once 'lib/simple_html_dom.php';
$url = "http://maps.google.com/maps/place?cid=6703996311168776503&q=hills+garage&hl=en&view=feature&mcsrc=google_reviews&num=20&start=0&ved=0CFUQtQU&sa=X&ei=sCq_Tr3mJZToygTOmuCGCg";
$html = file_get_html($url);
$ret = $html->find('div[id=pp-reviews]');
if(count($ret)==1){
echo $ret[0]->save();
}
else{
echo "Something went wrong";
}