TypeError:无法隐式地将'int'对象转换为str
我正在尝试编写一个文本游戏,我在我定义的函数中遇到了一个错误,让你在制作角色后基本上可以花费你的技能点数。起初,错误表明我试图从代码的这一部分中的整数中减去一个字符串: balance-strength
。显然这是错的,所以我用 strong = int(strength)
修复它......但是现在我收到了这个我以前从未见过的错误(新程序员)和我我很难知道它究竟要告诉我什么以及如何解决它。
I am trying to write a text game and I have run into an error in the function I am defining that lets you basically spend your skill points after you make your character. At first, the error stated that I was attempting to subtract a string from an integer in this part of the code:balance - strength
. Obviously that was wrong so I fixed it with strength = int(strength)
... but now I am getting this error which I have never seen before(new programmer) and I am stumped on what exactly it is trying to tell me and how I fix it.
这是我的函数部分无法正常工作的代码:
Here is my code for the part of the function that isn't working:
def attributeSelection():
balance = 25
print("Your SP balance is currently 25.")
strength = input("How much SP do you want to put into strength?")
strength = int(strength)
balanceAfterStrength = balance - strength
if balanceAfterStrength == 0:
print("Your SP balance is now 0.")
attributeConfirmation()
elif strength < 0:
print("That is an invalid input. Restarting attribute selection. Keep an eye on your balance this time!")
attributeSelection()
elif strength > balance:
print("That is an invalid input. Restarting attribute selection. Keep an eye on your balance this time!")
attributeSelection()
elif balanceAfterStrength > 0 and balanceAfterStrength < 26:
print("Ok. You're balance is now at " + balanceAfterStrength + " skill points.")
else:
print("That is an invalid input. Restarting attribute selection.")
attributeSelection()
这是我到达时的错误shell中代码的这一部分:
And here is the error I get when I get to this part of the code in the shell:
Your SP balance is currently 25.
How much SP do you want to put into strength?5
Traceback (most recent call last):
File "C:\Python32\APOCALYPSE GAME LIBRARY\apocalypseGame.py", line 205, in <module>
gender()
File "C:\Python32\APOCALYPSE GAME LIBRARY\apocalypseGame.py", line 22, in gender
customizationMan()
File "C:\Python32\APOCALYPSE GAME LIBRARY\apocalypseGame.py", line 54, in customizationMan
characterConfirmation()
File "C:\Python32\APOCALYPSE GAME LIBRARY\apocalypseGame.py", line 93, in characterConfirmation
characterConfirmation()
File "C:\Python32\APOCALYPSE GAME LIBRARY\apocalypseGame.py", line 85, in characterConfirmation
attributeSelection()
File "C:\Python32\APOCALYPSE GAME LIBRARY\apocalypseGame.py", line 143, in attributeSelection
print("Ok. You're balance is now at " + balanceAfterStrength + " skill points.")
TypeError: Can't convert 'int' object to str implicitly
有没有人知道怎么解决这个?提前谢谢。
Does anyone know how to solve this? Thanks ahead.
您无法使用字符串 C $ C> INT 。您需要使用 str $ c $将
int
转换为字符串
c>功能,或使用格式化
来格式化输出。
You cannot concatenate a string
with an int
. You would need to convert your int
to a string
using the str
function, or use formatting
to format your output.
更改: -
print("Ok. Your balance is now at " + balanceAfterStrength + " skill points.")
来: -
print("Ok. Your balance is now at {} skill points.".format(balanceAfterStrength))
或: -
print("Ok. Your balance is now at " + str(balanceAfterStrength) + " skill points.")
或根据评论,使用,
将不同的字符串传递给您打印
功能,而不是使用 +
连接: -
or as per the comment, use ,
to pass different strings to your print
function, rather than concatenating using +
: -
print("Ok. Your balance is now at ", balanceAfterStrength, " skill points.")