角UI路由器处理404

问题描述：

我有一个包装我的API调用服务的应用程序：

I have an app with a service which wraps my API calls:

var ConcernService = {
    ...
    get: function (items_url, objId) {
        var defer = $q.defer();
        $http({method: 'GET', 
            url: api_url + items_url + objId}).
            success(function (data, status, headers, config) {
                defer.resolve(data);
            }).error(function (data, status, headers, config) {
                console.log('ConcernService.get status',status);
                defer.reject(status);
            });
        return defer.promise;
    },

和我使用的UI路由器状态之间的过渡：

and I'm using UI-Router to transition between states:

concernsApp

    .config( function ($stateProvider, $urlRouterProvider) {

        $urlRouterProvider.otherwise("/404/");


        $stateProvider.state('project', {
        url: '/project/:projectId/',
        resolve: {
            project: function ($stateParams, ConcernService) {
                return ConcernService.get('projects/', $stateParams.projectId);
            },
        },
        views: {
            ...
        }
    });

我是从使用正常Angualr路由器移动和我有困难，了解如何实现404。我可以看到 ConcernService 投掷的console.log 地位拒绝，但我要如何抓住这个在国家路由器？

I'm moving from using the normal Angualr router and I'm having difficulty understanding how to implement 404s. I can see the ConcernService throwing the console.log status as rejected, but how do I catch this in the state router?

任何帮助非常AP preciated。

Any help much appreciated.

答

的否则（）规则仅调用时没有其他的路线的匹配。你真正需要的是拦截 $ stateChangeError 事件，这是出问题的时候的状态转变（例如，解决失败的）什么被炒鱿鱼。你可以阅读更多有关在状态更改事件文档。

The otherwise() rule is only invoked when no other route matches. What you really want is to intercept the $stateChangeError event, which is what gets fired when something goes wrong in a state transition (for example, a resolve failing). You can read more about that in the state change event docs.

你正在试图做的是这样的事情什么最简单的实现：

The simplest implementation for what you're trying to do would be something like this:

$rootScope.$on('$stateChangeError', function(event) {
  $state.go('404');
});

此外，由于 $ HTTP 本身是建立在承诺（其中解析解析），你的 ConcernService 方法可以简化为一个班轮（我知道你扩大它用于调试目的，但你可以有很容易链接，只是供参考）：

Also, since $http itself is built on promises (which resolve resolves), your ConcernService method can be simplified down to a one-liner (I realize you expanded it for debugging purposes, but you could have just as easily chained it, just FYI):

var ConcernService = {

  get: function (items_url, objId) {
    return $http.get(api_url + items_url + objId);
  }
}

角UI路由器处理404

相关推荐