如何在 Swift 中将协议作为参数传递

问题描述：

在 Objective-C 中，我知道如何将 protocol 作为参数传递:

In Objective-C, I know how passing a protocol as parameter:

- (void)MyMethod:(Protocol *)myparameter

但是在 Swift 中没有更多的 Protocol 类型.

But in Swift there is no more Protocol type.

如何在不知道哪个是协议的情况下将协议作为参数传递?

How can I pass a protocol as parameter without knowing which is ?

答

在您的评论之一中，您说:

In one of your comments you say:

我想创建一个方法，该方法返回实现所需协议的类类型数组."

"I want create a method which return an array of type of class which implements a desired protocol."

您是否尝试过以下操作:

Have you tried something like the following:

//notice the use of @objc here
@objc protocol AlertProtocol
{
    func getMyName()->String
}

class Class1 : AlertProtocol
{
     let name = "Object 1"
     func getMyName() -> String
    {
        return name
    }
}

class Class2 : AlertProtocol
{
    let name = "Object 2"
    func getMyName() -> String
    {
        return name
    }
}

//borrowing from and refactoring siLo's answer
func classesConformingToProtocol(proto:Protocol) -> [AnyClass]
{
    let availableClasses : [AnyClass] = [ Class1.self, Class2.self ]

    var conformingClasses = Array<AnyClass>()

    for myClass : AnyClass in availableClasses
    {
        if myClass.conforms(to: proto)
        {
            conformingClasses.append(myClass)
        }
    }

    return conformingClasses
}

然后像这样使用上面的结构:

Then use the above structure like this:

let classes = classesConformingToProtocol(AlertProtocol.self)

完成这项工作的棘手部分是@objc"，它将协议暴露给目标 c 运行时，并允许我们将任何协议类型"作为参数传递.

The tricky part that does the work is the "@objc" that exposes the protocol to the objective c runtime and allows us to pass any "Protocol Type" as a parameter.

可能在未来的某个时候，我们将能够以纯粹的"Swift 方式做到这一点.

Probably at some point in the future we will be able to do this in a "pure" Swift way.

如何在 Swift 中将协议作为参数传递

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