＆QUOT;分配丢弃“const”限定符＆QUOT;错误的非const指针

在下面的函数：

char *mystrtok(const char *input, const char *delim,char *rest) {
    int i;
    for (i = 0; input[i] != *delim && input[i] != '\0'; ++i) {
        continue;
    }
    char *result = malloc(sizeof(char) * (i + 2));
    memcpy(result, input, i + 1);
    result[i + 1] = '\0';
    if (input[i + 1] != '\0') 
        rest = input + i + 2;
    else
        rest = NULL;
    return result;
}

我收到分配丢弃'常量'指针目标类型的限定词的行休息=输入+ I + 2 ，但是，正如你所看到的，其余的是不是一个常量指针。我在做什么错在这里？

I am getting assignment discards 'const' qualifier from pointer target type for the line rest = input + i + 2, however, as you can see, rest is not a constant pointer. What am I doing wrong here?