比较在PHP中两个数组的值

问题描述：

您好我想比较2阵列的所有值，并用真或假的结束。我使用下面的code和会的想到结果会是假的。但事实并非如此，当最后一行运行我希望显示类似

Hi i want to compare all the values of 2 arrays and end up with a true or false . I am using the code below and would of thought that the result would be false . but that is not the case , when the last line runs I would expect a display something like

阵列（[0] => 0）

Array ( [0] => 0 )

但我没有得到任何显示，以便认为PHP是高兴，没有什么区别

but I get no display so assume that php is happy that there is no difference

我的code是

        $before = array('1', '1', '0', '0', '1', '0' ) ;
        $after =  array('0', '1', '0', '0', '1', '0' ) ;

        $new_array= array_diff($before,$after);

        print_r ($new_array) ;

想必和array_diff应该在这里发现了一个区别？任何帮助将是巨大的感谢

surely the array_diff should spot a difference here ? any help would be great thanks

答

和array_diff 给出了元素在 $之前而不是 $后 。由于这两种阵列包括 0 和 1 ，它返回一个空数组。

array_diff gives which elements are in $before but not $after. Since both arrays consist of '0' and '1', it returns an empty array.

什么你要找的是 和array_diff_assoc ，它看起来在键值在一起。

What you're looking for is array_diff_assoc, which looks at keys and values together.

待办事项，输出你不会是阵列（[0] = 0），而阵列（[0] =方式＆gt; 1），因为它给从没有在另一个存在的第一个阵列中的元素

Do note, the output you get will not be Array( [0] => 0 ), but rather Array( [0] => 1 ), as it gives the elements from the first array that doesn't exist in the other one.

如果你希望其他的输出，你需要做的和array_diff_assoc（$后，前$）。

If you wish the other output, you'll need to do array_diff_assoc($after, $before).

比较在PHP中两个数组的值

相关推荐