在列表中查找子列表的开始和结束索引

问题描述：

我有一个列表:

greeting = ['hello','my','name','is','bob','how','are','you']

我想定义一个函数，该函数将在此列表中找到子列表的第一个和最后一个索引.因此:

I want to define a function that will find the first and last index of a sublist in this list. Thus:

find_sub_list(['my','name','is'], greeting)

应返回:

1, 3

建议?

答

如果您要进行多个匹配，则可以这样做:

If you want multiple matches, this works:

greeting = ['hello','my','name','is','bob','how','are','you','my','name','is']

def find_sub_list(sl,l):
    results=[]
    sll=len(sl)
    for ind in (i for i,e in enumerate(l) if e==sl[0]):
        if l[ind:ind+sll]==sl:
            results.append((ind,ind+sll-1))

    return results

print find_sub_list(['my','name','is'], greeting) 
# [(1, 3), (8, 10)]

或者，如果您只想要第一个比赛:

Or if you just want the first match:

greeting = ['hello','my','name','is','bob','how','are','you','my','name','is']

def find_sub_list(sl,l):
    sll=len(sl)
    for ind in (i for i,e in enumerate(l) if e==sl[0]):
        if l[ind:ind+sll]==sl:
            return ind,ind+sll-1

print find_sub_list(['my','name','is'], greeting)    
# (1, 3)

在列表中查找子列表的开始和结束索引

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