在Python中合并字典列表中的重复项

问题描述：

我有一个python词典列表.现在，我正在尝试基于python中的特定键实体合并这些字典.字典列表的示例是:

I have a list of dictionaries in python. And now i am trying to merge these dictionaries based on a specific key entity in python. Example the list of dictionary is:

[[{'max_score': u'110', 'total_mark': u'75', 'student': <student_details: Komal>}, {'max_score': u'110', 'total_mark': u'75', 'student': <student_details: Java>}],
 [{'max_score': u'131', 'total_mark': u'99', 'student': <student_details: Komal>}, {'max_score': u'131', 'total_mark': u'64', 'student': <student_details: Java>}],
 [{'max_score': u'138', 'total_mark': u'110', 'student': <student_details: Komal>}, {'max_score': u'138', 'total_mark': u'80', 'student': <student_details: Java>}]]

我正在尝试将此记录转换为单个记录，例如:

and i am trying to convert this record in their single individual records like:

    ['student': <student_details: Komal>:[
{'max_score': u'110', 'total_mark': u'75', }
{'max_score': u'131', 'total_mark': u'99'},
{'max_score': u'138', 'total_mark': u'110'}],
'student': <student_details: Java>:[
{'max_score': u'110', 'total_mark': u'75'}, 
{'max_score': u'131', 'total_mark': u'64'}, 
{'max_score': u'138', 'total_mark': u'80'}]]

请给我建议我该如何实现.预先感谢.

please suggest me how can i achieve that. Thanks in advance.

答

可能最接近预期输出的是:

Probably the closest you could come to your expected output is:

studs = [
 [{'max_score': u'110', 'total_mark': u'75', 'student': '<student_details: Komal>'}, 
  {'max_score': u'110', 'total_mark': u'75', 'student': '<student_details: Java>'}], 
 [{'max_score': u'131', 'total_mark': u'99', 'student': '<student_details: Komal>'}, 
  {'max_score': u'131', 'total_mark': u'64', 'student': '<student_details: Java>'}], 
 [{'max_score': u'138', 'total_mark': u'110', 'student': '<student_details: Komal>'}, 
  {'max_score': u'138', 'total_mark': u'80', 'student': '<student_details: Java>'}]]


d={}
for studlist in studs:
    for stud in studlist:
        # use the 'student' - entry as tuple as key and append a set of each scores data
        d.setdefault( ('student',stud['student']) , []).append(
            { 'max_score' : stud['max_score'], 'total_mark': stud['total_mark'] })

print(d)

输出:

{('student', '<student_details: Komal>'): 
    [{'max_score': '110', 'total_mark': '75'}, 
     {'max_score': '131', 'total_mark': '99'}, 
     {'max_score': '138', 'total_mark': '110'}], 
('student', '<student_details: Java>'): 
    [{'max_score': '110', 'total_mark': '75'}, 
     {'max_score': '131', 'total_mark': '64'}, 
     {'max_score': '138', 'total_mark': '80'}]
}

这是一个以tuples作为key的集合，元组是('student', 'your details')，而您的得分中dict的list值.您需要一个可哈希的类型作为dict的键-元组是不可变的，因此可哈希且可作为键有效.

Which is a set with tuples as key, the tuples are ('student', 'your details') and values of list of dict of your scores. You need a hashable type as key into a dict - tuples are immutable and thus hashable and valid as key.

在Python中合并字典列表中的重复项

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