没有这样的方法访问JAX RS CXF Web服务时出错

问题描述：

当我尝试访问我的JAX RS CXF Web服务时，没有出现此类方法错误。
这些是我在构建路径中添加的jar：

I am getting no such method error when I try to access my JAX RS CXF web service. These are the jars that I have added in the build path:

cxf-core-3.1.2.jar
cxf-rt-frontend-jaxrs-3.1.2.jar
cxf-rt-rs-client-3.1.2.jar
cxf-rt-rs-extension-providers-3.1.2.jar
cxf-rt-rs-extension-search-3.1.2.jar
cxf-rt-transports-http-3.1.2.jar
httpclient-4.4.1.jar
httpcore-4.4.1.jar
httpcore-nio-4.4.1.jar
javax.ws.rs-api-2.0.1.jar
jcl-over-slf4j-1.7.12.jar
jettison-1.3.7.jar
spring-aop-4.1.6.RELEASE.jar
spring-beans-4.1.6.RELEASE.jar
spring-context-4.1.6.RELEASE.jar
spring-core-4.1.6.RELEASE.jar
spring-expression-4.1.6.RELEASE.jar
spring-web-4.1.6.RELEASE.jar
stax2-api-3.1.4.jar
xml-resolver-1.2.jar
xmlbeans-2.6.0.jar
xmlschema-core-2.2.1.jar    
xmlsec-2.0.5.jar

J2EE版本为2.3，应用服务器是weblogic 12

J2EE version is 2.3, Application server is weblogic 12

我知道这是个jar问题。但是我无法解决它。这是引发的错误：

I know it is some jar issue. But I am not able to resolve it. This is the error thrown:

java.lang.NoSuchMethodError: javax.ws.rs.NotFoundException.validate(Ljavax/ws/rs/core/Response;Ljavax/ws/rs/core/Response$Status;)Ljavax/ws/rs/core/Response;
    at javax.ws.rs.NotFoundException.(NotFoundException.java:126)
    at org.apache.cxf.jaxrs.utils.SpecExceptions.toNotFoundException(SpecExceptions.java:89)
    at org.apache.cxf.jaxrs.utils.ExceptionUtils.toNotFoundException(ExceptionUtils.java:122)
    at org.apache.cxf.jaxrs.interceptor.JAXRSInInterceptor.processRequest(JAXRSInInterceptor.java:169)

答

该类和方法可能存在并且与任何weblogic jar冲突

The class and method might be present and conflicting with any of the weblogic jars

在WEB-INF中存在的weblogic.xml中，添加javax.ws.rs。*程序包，以指示weblogic首选WAR类路径中的程序包，如下所示，

In your weblogic.xml present in WEB-INF, add javax.ws.rs.* package to instruct weblogic to prefer the package from your WAR classpath as shown below,

< package-name> javax.ws.rs。*< / package-name>

示例weblogic.xml：

Sample weblogic.xml:

    <?xml version="1.0" encoding="UTF-8"?>  
<weblogic-web-app xmlns="http://xmlns.oracle.com/weblogic/weblogic-web-app" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsdhttp://xmlns.oracle.com/weblogic/weblogic-web-apphttp://xmlns.oracle.com/weblogic/weblogic-web-app/1.0/weblogic-web-app.xsd">
    <container-descriptor>  
        <prefer-application-packages>  
            <package-name>com.fasterxml.jackson.*</package-name>
            <package-name>org.eclipse.persistence.*</package-name>
            <package-name>javax.ws.rs.*</package-name>
        </prefer-application-packages>  
    </container-descriptor>  
</weblogic-web-app>

没有这样的方法访问JAX RS CXF Web服务时出错

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