JavaScript测试(object&& object！=="null"&& object！=="undefined")
问题描述：
我似乎经常使用此测试
if( object && object !== "null" && object !== "undefined" ){
doSomething();
}
关于 objects 的问题，我从服务调用或读取cookie回来(因为不同的浏览器返回不同的值 null ， undefined ，"null" 或"undefined" ).
on objects I get back from a service call or from reading cookies (since different browsers return the different values null, undefined, "null", or "undefined").
有没有更简单/更有效的方法来进行此检查?
Is there an easier/more efficient way of doing this check?
答
我认为您不能使它变得更简单，但是您当然可以将该逻辑重构为一个函数:
I don't think you can make that any simpler, but you could certainly refactor that logic into a function:
function isRealValue(obj)
{
return obj && obj !== 'null' && obj !== 'undefined';
}
然后，至少您的代码变为:
Then, at least your code becomes:
if (isRealValue(yourObject))
{
doSomething();
}