为什么我不能在PHP的DateTime类中访问DateTime-> date?

问题描述：

如果我尝试运行以下代码，请使用DateTime类:

Using the DateTime class, if I try to run the following code:

$mydate = new DateTime();
echo $mydate->date;

我会找回此错误消息

通知:未定义的属性:DateTime :: $ date ...

Notice: Undefined property: DateTime::$date...

这没有意义，因为在变量$mydate上运行var_dump()时，它清楚地表明此属性存在并且可以公开访问:

Which doesn't make sense because when running var_dump() on the variable $mydate, it clearly shows that this property exists and is publicly accessible:

var_dump($mydate);

object(DateTime)[1]
  public 'date' => string '2012-12-29 17:19:25' (length=19)
  public 'timezone_type' => int 3
  public 'timezone' => string 'UTC' (length=3)

这是PHP中的错误，还是我做错了什么?我正在使用PHP 5.4.3.

Is this a bug within PHP or am I doing something wrong? I'm using PHP 5.4.3.

答

这是已知问题

可用的日期实际上是对var_dump()的支持的副作用– derick@php.net

Date being available is actually a side-effect of support for var_dump() here – derick@php.net

由于某些原因，您不应该能够访问该属性，但是无论如何var_dump都会显示该属性.如果您确实希望以这种格式获取日期，请使用 DateTime::format() 函数.

For some reason, you're not supposed to be able to access the property but var_dump shows it anyways. If you really want to get the date in that format, use the DateTime::format() function.

echo $mydate->format('Y-m-d H:i:s');

为什么我不能在PHP的DateTime类中访问DateTime-> date?

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