指向引用的指针

asdf写道：

asdf wrote:

C ++允许引用指针，但不允许指向

参考，为什么？

C++ allows a reference to a pointer, but doesn''t allow a pointer to a
reference, why?

它的目的是什么？

What would be its purpose?

asdf写道：

asdf wrote:

C ++允许引用指针，但是不允许指向

引用，为什么？

C++ allows a reference to a pointer, but doesn''t allow a pointer to a
reference, why?

你错了：


int main（）

{

int i;

int& ref_i = i; //引用int

int * p =& i; //指向int的指针

int * p_ref =& ref_i; //指向int的引用的指针。

}


p_ref是指向引用的指针。现在引用只是另一个变量的别名

，所以p_ref == p，但这仍然与你的

前提相矛盾。


祝你好运，


Tom

You''re mistaken:

int main()
{
int i;
int& ref_i = i; // reference to an int
int* p = &i; // pointer to an int
int* p_ref = &ref_i; // pointer to a reference to an int.
}

p_ref is a pointer to a reference. Now a reference is simply an alias
for another variable, so p_ref==p, but that still contradicts your
premise.

Best regards,

Tom

Thomas Tutone< Th ******** ***@yahoo.comwrote：

Thomas Tutone <Th***********@yahoo.comwrote:

asdf写道：

asdf wrote:

> C ++允许引用一个指针，但不允许指向
引用，为什么？

>C++ allows a reference to a pointer, but doesn''t allow a pointer to a
reference, why?

你错了：


int main（）

{

int i;

int& ref_i = i; //引用int

int * p =& i; //指向int的指针

int * p_ref =& ref_i; //指向int的引用的指针。

}


p_ref是指向引用的指针。

You''re mistaken:

int main()
{
int i;
int& ref_i = i; // reference to an int
int* p = &i; // pointer to an int
int* p_ref = &ref_i; // pointer to a reference to an int.
}

p_ref is a pointer to a reference.

我倾向于不同意。一旦参考坐下，任何使用它

实际上是指引用的对象，所以（p_ref =& ref_i）真的意味着

（p_ref =& i ），所以它是一个指向引用对象的指针，但不是

实际上是指向实际引用的指针。虽然，这可能会分裂

头发，我可以看到你的解释也可以看作是正确的，

因为参考文献本身并不存在。

I tend to disagree. Once a reference has been seated, any use of it
really refers to the referenced object, so (p_ref = &ref_i) really means
(p_ref = &i), so it is a pointer to the referenced object, but not
really a pointer to the actual reference. Though, this may be splitting
hairs, and I can see how your interpretation can be seen as correct too,
since a reference doesn''t really exist on its own.

现在引用只是别名

另一个变量，所以p_ref == p，

Now a reference is simply an alias
for another variable, so p_ref==p,

我同意。

This I agree with.

但这仍然与你的
前提相矛盾。

but that still contradicts your
premise.

-

Marcus Kwok

将''invalid''替换为''net''来回复

--
Marcus Kwok
Replace ''invalid'' with ''net'' to reply