Mongodb:从mongo shell中的ObjectId执行日期范围查询

问题描述：

我有一个看起来像这样的收藏集:

I have a collection that looks like this:

{
  _id: ObjectId("50a68673476427844b000001"),
  other fields
}

我想进行范围查询以查找两个日期之间的记录.我知道我可以从mongo shell var中的ObjectId获取日期:

I want to do a range query to find records between two dates. I know that I can get the date from the ObjectId in the mongo shell var doing this:

var aDate = ObjectId().getTimestamp()

但是(目前为止我无法确定)没有办法创建仅包含时间戳部分的ObjectId-我认为我的理想解决方案是使Mongo Shell代码不起作用:>

but there isn't a way (as far as I can figure out at the moment) to create an ObjectId consisting of just the timestamp portion - I think my ideal solution is non-functioning mongo shell code would be:

var minDate = ObjectId(new Date("2012-11-10"));
var maxDate = ObjectId(new Date("2012-11-17"));

将查找结果与minDate和MaxDate用作范围值.

Use the find with the minDate and MaxDate as the range values.

SHELL中有没有办法做到这一点-我对某些驱动程序产品不感兴趣.

Is there a way to do this in the SHELL - I'm not interested in some of the driver products.

答

您可以通过2个步骤进行操作:

You can do that in 2 steps:

 var objIdMin = ObjectId(Math.floor((new Date('1990/10/10'))/1000).toString(16) + "000
0000000000000")
 var objIdMax = ObjectId(Math.floor((new Date('2011/10/22'))/1000).toString(16) + "000
    0000000000000")
 db.myCollection.find({_id:{$gt: objIdMin, $lt: objIdMax}})

或一步(不太容易理解):

or in one step (what is less readable):

db.myCollection.find({_id:{$gt: ObjectId(Math.floor((new Date('1990/10/10'))/1000).toString(16) + "000
    0000000000000"), $lt: ObjectId(Math.floor((new Date('2011/10/10'))/1000).toString(16) + "000
    0000000000000")}})

Mongodb:从mongo shell中的ObjectId执行日期范围查询

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