根据Mathematica中的另一个列表值拆分列表
问题描述:
在Mathematica中,我有一个点坐标列表
In Mathematica I have a list of point coordinates
size = 50;
points = Table[{RandomInteger[{0, size}], RandomInteger[{0, size}]}, {i, 1, n}];
以及这些点所属的聚类索引列表
and a list of cluster indices these points belong to
clusterIndices = {1, 1, 1, 1, 1, 1, 1, 2, 2, 1, 2, 1, 2, 1, 1, 1, 1, 1, 1, 1};
基于clusterIndices值将点分为两个单独的列表的最简单方法是什么?
what is the easiest way to split the points into two separate lists based on the clusterIndices values?
我想出的解决方案:
pointIndices =
Map[#[[2]] &,
GatherBy[MapIndexed[{#1, #2[[1]]} &, clusterIndices], First],
{2}];
pointsByCluster = Map[Part[points, #] &, pointIndices];
有更好的方法吗?
答
如何?
points[[
Flatten[Position[clusterIndices, #]]
]] & /@
Union[clusterIndices]