将表单提交到php文件中的特定函数

问题描述：

So I have a form in index.php

  <? requireonce("action.php"); ?>
  <form action="action.php" method="post">
    //stuff
  </form>

I also have a function to handle that form in action.php

<? 
   function formHandle(){
      //stuff
   }
?>

How do I pass the form to formHandle() entirely within index.php? I don't want to call formHandle() in action.php because it's required in index.php - and I don't want it to run upon page opening.

所以我在index.php code> p> 中有一个表格

 ＆lt;？  requireonce（ “action.php的”）;  ？＆gt; 
＆lt; form action =“action.php”method =“post”＆gt; 
 // stuff 
＆lt; / form＆gt; 
  code>  pre> 
 
 我还有一个函数来处理 action.php  code>  p> 
 
 
 ＆lt;？  
 function formHandle（）{
 // stuff 
} 
？＆gt; 
  code>  pre> 
 
 如何将表单传递给 formHandle（）   code>完全在 index.php  code>中？ 我不想在 action.php  code>中调用 formHandle（） code>，因为它在 index.php  code>中是必需的 - 我不想要它 在页面打开时运行。 p> 
  div>

答

You can do so in action.php

<?php

if(isset($_POST['myform'])){

formHandle();  // call to a function
}

?>

答

Change your action to index.php and call formHandle from within index.php.

<? require_once("action.php"); ?>
<form action="index.php" method="post">
    //stuff
</form>

答

You cannot submit "to a function". Browsers don't care about server-side languages. Browsers communicate via HTTP. HTTP has no concept of "functions" or specific programming languages. You submit something to a URL, and the server handles whatever happens at that URL.

将表单提交到php文件中的特定函数

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