我需要帮助解析php上的json url

问题描述：

Here is the json content:

{
   "success":true,
    "data":"{\"campaign_name\":\"helloworld\",\"download_link\":\"https:\\\/\\\/google.com\\\/accesskey\\\/getfile\\\/m-spqn-e61-2aef2575a0b5250354f2b0fda033e703?token=HUSYjdC5jyJskXUHiKn13l1A1BaAjH2R&dcma=5ecceb0522bcd0db\",\"link\":\"http:\\\/\\\/www.lol.com\\\/remove\\\/remove.php\"}",
    "message":null
}

I'm looking to get the value of download_link. How can I do that?

This is what I tried:

<?php
$jsndata = {"success":true,"data":"{\"campaign_name\":\"helloworld\",\"download_link\":\"https:\\\/\\\/google.com\\\/accesskey\\\/getfile\\\/m-spqn-e61-2aef2575a0b5250354f2b0fda033e703?token=HUSYjdC5jyJskXUHiKn13l1A1BaAjH2R&dcma=5ecceb0522bcd0db\",\"link\":\"http:\\\/\\\/www.lol.com\\\/remove\\\/remove.php\"}","message":null};
$jsn = json_decode($jsndata,true);

$temperatureMin = $jsn['data'][6]['download_link'];
echo $temperatureMin;
 ?>

以下是json内容： p>

  {
“ 成功“：true，
”数据“：”{\“campaign_name \”：\“helloworld \”，\“download_link \”：\“https：\\\ / \\\ / google.com \\\ /  ACCESSKEY \\\ / GETFILE \\\ / M-spqn-e61-2aef2575a0b5250354f2b0fda033e703标记= HUSYjdC5jyJskXUHiKn13l1A1BaAjH2R＆安培; DCMA = 5ecceb0522bcd0db \ “\ ”链接\？“：\” HTTP：\\\ / \\\ / www.lol。  com \\\ / remove \\\ / remove.php \“}”，
“message”：null 
} 
  code>  pre> 
 
 我正在寻找 获取download_link的值。 我该怎么做？ p> 
 
 
这就是我的尝试： p> 
 
 
 ＆lt;？php 
 $ jsndata = {“success”  ：真 “数据”： “{\” CAMPAIGN_NAME \ “：\” 的HelloWorld \ “\ ”DOWNLOAD_LINK \“：\” HTTPS：\\\ / \\\ / google.com \\\ / ACCESSKEY \\\  / GETFILE \\\ / M-spqn-e61-2aef2575a0b5250354f2b0fda033e703标记= HUSYjdC5jyJskXUHiKn13l1A1BaAjH2R＆安培; DCMA = 5ecceb0522bcd0db \ “\ ”链接\？“：\” HTTP：\\\ / \\\ / www.lol.com \\\  /remove\\\/remove.php\"}","message":null};
$jsn = json_decode（$ jsndata，true）; 
 
 $ temperatureMin = $ jsn ['data'] [6  ] ['download_link']; 
echo $ temperatureMin; 
？＆gt; 
  code>  pre> 
  div>

答

You have a json object containing another serialized json object.

Decode the first object, get the second serialized object and decode that:

$jsndata = '{
    "success":true,
    "data":"{\"campaign_name\":\"helloworld\",\"download_link\":\"https:\\\/\\\/google.com\\\/accesskey\\\/getfile\\\/m-spqn-e61-2aef2575a0b5250354f2b0fda033e703?token=HUSYjdC5jyJskXUHiKn13l1A1BaAjH2R&dcma=5ecceb0522bcd0db\",\"link\":\"http:\\\/\\\/www.lol.com\\\/remove\\\/remove.php\"}",
    "message":null
}';

// Decode the main json object
$jsn = json_decode($jsndata,true);

// Since 'data' is another serialized object, you need to decode that as well:
$data = json_decode($jsn['data'], true);

// Now you can access the contents of 'data'
echo $data['download_link'];

Demo: https://3v4l.org/1PcQp

答

You need:

- quotes around your JSON
- to remove the quotes around the inner object

$jsndata = '{"success":true,"data":{\"campaign_name\":\"helloworld\",\"download_link\":\"https:\\\/\\\/google.com\\\/accesskey\\\/getfile\\\/m-spqn-e61-2aef2575a0b5250354f2b0fda033e703?token=HUSYjdC5jyJskXUHiKn13l1A1BaAjH2R&dcma=5ecceb0522bcd0db\",\"link\":\"http:\\\/\\\/www.lol.com\\\/remove\\\/remove.php\"},"message":null}' ;

And you need to remove the [6] from your array access:

$temperatureMin = $jsn['data']['download_link'];

我需要帮助解析php上的json url

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