如何通过每种颜色的分数贡献在n种颜色之间插值？

如何在n种颜色之间插值。

How can I interpolate between n colors.

两种颜色的简单案例

先考虑一个更简单的案例，我们要找到两种颜色的中点。

Consider a more simple case first, where we want to find the mid-point of 2 colors.

Color1 is RGB ( 255, 0, 0 ) // Red
Color2 is RGB ( 128, 128, 128 ) // Grey

RGB ( 128 + 64, 128 / 2, 128 / 2 ) = RGB ( 192, 64, 64 )

由于中点正好在两者之间，与插值存在线性关系，那么它可以通过在Color1和Color2之间的小数量（例如0.25）进行插值，颜色应该更接近Color1。

Since the mid-point is exactly in between the two and there is a linear relationship to the interpolation, then its possiable to interpolate by a fractional amount such as 0.25 between Color1 and Color2, the color should be closer to Color1.

RGB ( 255 - 32, 32, 32 ) = RGB ( 223, 32, 32 )

b $ b

n种颜色的情况

我希望找到解决方案的案例是有n种颜色，具有最多为1.0的分数加权。

The case I wish to find a solution for is where there are n colors where each color has a fractional weighting totaling up to 1.0.

（猜测，我猜每种颜色可以被认为是3维空间中的一个点，内插点对每个色点）

(Guessing, I guess each color could be considered to be a point in a 3 dimensional space and the weighting describes how far relatively the interpolated point is to each color point)

颜色插值只是线性RGB。

The color interpolation is linear RGB only.

在某些情况下我想有可能是多个整数值的解决方案的问题，例如，如果有几个颜色具有相似的值。

Under some conditions I guess there MAY be multiple integer values which are solutions to the problem, for example if there are a n few colors which have similar value.

我读到有双线性

通常颜色数不会超过5，通常是2,3或4种颜色。

Usually the number of colors wouldn't exceed 5, it would usually be 2, 3 or 4 colors.