如何使用modelAttribute在ajax（jquery）中提交spring表单

问题描述：

我是Spring MVC的新手。
我有一个这样的表格，

I am new to Spring MVC. I have a form like this,

< form：form acion =/ myaction.htmmethod =post modelAttribute =myFormid =formid> 和一个返回json的控制器

<form:form acion="/myaction.htm" method="post" modelAttribute="myForm" id="formid"> and a controller that returns json

public @ResponseBody ResultObject doPost（@ModelAttribute（myForm）MyForm myForm）{ sysout（myform.input）; }

我可以使用 $（＃formid）提交此项。（提交））; 和我的modelAttribute工作正常，从UI中获取值。

I am able to submit this using$("#formid").submit(); and my modelAttribute is working fine, taking values from UI.

我的问题是，如何以jquery ajax方式提交此表单？
我试过这个，

my question is, how to submit this form in jquery ajax way? I tried this,

$.ajax({
type:"post",
url:"/myaction.htm",
async: false,
dataType: "json",
success: function(){
alert("success");
}

});

表单已提交，但modelAttribute值为空，如何包含modelAttribute对象（表单正在使用的对象））提交时？

the form is submitted but modelAttribute values are nulls, how to include modelAttribute object(object that form is using) while submitting?

答

您需要发布数据。我通常使用以下方式。

You need to post the data. The way I typically do it is using the following.

var str = $("#myForm").serialize();

$.ajax({
    type:"post",
    data:str,
    url:"/myaction.htm",
    async: false,
    dataType: "json",
    success: function(){
       alert("success");
    }
});

如何使用modelAttribute在ajax（jquery）中提交spring表单

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