C#pinvoke封送处理工会

将C Union转换为C#时遇到了一些问题.这是联盟的定义:

I got some problems translating a C Union to C#. Here's the definition of the Union:

union Info
{
    char        varChar[8];
    short       varShort[4];
    int         varInteger[2];
    float       varFloat[2];
    double      varDouble;
    __int64     varInteger64;
    char        varSzText[8];   
};

这是我在C#中的尝试之一:

And here is one of my tries in C#:

[StructLayout(LayoutKind.Explicit)]
public struct Info
{
    [FieldOffset(0)]
    [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 8)]
    public string varChar;

    [FieldOffset(0)]
    [MarshalAs(UnmanagedType.ByValArray, ArraySubType = UnmanagedType.I2, SizeConst = 4)]
    public short[] varShort;

    [FieldOffset(0)]
    [MarshalAs(UnmanagedType.ByValArray, ArraySubType = UnmanagedType.I4, SizeConst = 2)]
    public int[] varInteger;

    [FieldOffset(0)]
    [MarshalAs(UnmanagedType.ByValArray, ArraySubType = UnmanagedType.R4, SizeConst = 2)]
    public float[] varFloat;

    [FieldOffset(0)]
    public double varDouble;

    [FieldOffset(0)]
    public long varInteger64;

    [FieldOffset(0)]
    [MarshalAs(UnmanagedType.ByValArray, ArraySubType = UnmanagedType.LPStr, SizeConst = 8)]    //LPStr, LPWStr, BStr oder LPTStr 
    public string[] varSzText;
};

我可能在这里做错了一切.我读了一些有关引用和值类型的内容，并且它们在内存布局中的处理方式有所不同.因为这里的大多数字段都是数组，所以我猜它们是值类型.这意味着它们不是全部都位于[FieldOffset(0)]吗?

I probably do everything wrong here. I read something about reference- and value types and that they are treated differently in the memory layout. Since most of the fields here are arrays, I guess, those are value types. Which means they are not all at [FieldOffset(0)]?

另一个麻烦的是最后一个字段varSzText. 我有一个示例C/C ++程序，它使用此字段，如下所示: printf("Text: %s\n", &info.varSzText[0]); 我的C不太好，但是如果我的解释正确，那么char varSzText[8];会将地址存储到(\ 0终止)字符串中.该示例程序至少会打印20多岁的字符串.

Another headache is the last field varSzText. I got a sample C/C++ programm which uses this field as follows: printf("Text: %s\n", &info.varSzText[0]); My C isn't very good but if my interpretation is right, then char varSzText[8]; stores addresses to (\0-terminated) strings. The sample program prints at least a 20-something character string.

• 有人可以告诉我，如何组织这个工会吗?
• 我在发布之前在论坛上进行了搜索和搜索，但大多数情况下，我发现了具有简单类型(没有数组/字符串)的真正简单的联合体.有人知道有关pinvoke/封送处理的很好的读物吗?

我发现，该联合仅在具有类型字段的结构中使用，该结构为我提供了有关联合中实际存储的内容的提示.因此，我将坚持使用Deduplicator的回答.我将为每个字段创建不同的结构，然后根据类型字段解析联合.

I found out, that the union is only used within a struct which has a type-field which gives me a hint on what is actually stored in the union. Therefore I'll stick with Deduplicator's answere. I'll create different structs for each field and parse the union according to the type-field.