如何替换除文本以外的所有内容[重复]

问题描述：

This question already has an answer here:

How do I replace certain parts of my string? 5 answers

I'm looking to replace every thing except text between two string in php example: Watch Sidney's video

i want to replace "Watch 's video" with nothing and just keep "Sidney"

need to be in this format preg_replace("regex code", "replace with", input text)

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此问题已经存在这里有一个答案： p>

如何替换字符串的某些部分？ 5个答案\ r span> li> ul> div>
我正在寻找替换除了两个文本之外的所有东西 php中的字符串 example：观看Sidney的视频 p>

我想用什么都不取代“观看视频”，只需保留“Sidney” p>

需要以这种格式preg_replace（“正则表达式代码”，“替换为”，输入文本） p> div>

答

You can do it using the following regex :

/Watch (\w*)'s video/

and you can replace with \1

Live demo here

Update

Sample code in php :

echo preg_replace('/Watch (\w*)\'s video/', "\\1", 'Watch Sidney\'s video');

Output

Sidney

答

You can make use of following explode() function for this:

$returnValue = explode(' ', 'Watch Sidney\'s video');

This will return an array as:

array (
  0 => 'Watch',
  1 => 'Sidney's',
  2 => 'video',
)

Now check the entries of array for string with 's and once you get it, trim 's off as :

$myString  str_replace("\'s","",$returnValue[some_index]);

答

This'll give you the text between the first space and the first apostrophe (assuming these criteria are constant):

<?php
$message = "Watch Sidney's video";
$start = strpos($message, " ");
$finish = strpos($message, "'");
echo substr($message, $start, $finish-$start);

答

// replace apostrophe (') or words without possessive contraction ('s) (Watch, video) with empty string
preg_replace("/(?:'|\s?\b\w+\b\s?)(?!'s)/", "", "Watch Sidney's video") // => Sidney

Try it here: https://regex101.com/r/sC7GyQ/1

答

If you want to extract video author's name - you may use extracting preg_match like this:

$matches = [];
preg_match('@Watch (\w+)\'s video@', $source, $matches);

echo $matches[1];

如何替换除文本以外的所有内容[重复]

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