可以用静态链接构建一个共享库使用库？
我可以使用带有静态链接的gcc构建可执行文件：
I can build a executable with gcc with static link:
gcc -static xxx.c -o xxx
gcc -static xxx.c -o xxx
所以我可以运行xxx没有任何外部依赖库。
So I can run xxx without any external dependent library.
但是如果我想构建没有externel依赖库的共享库？我想要
共享库静态链接其外部引用。
But what if I want to build shared library without externel dependent library? which I mean I want the shared library statically linked its externel reference in.
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This will work:
# Generate position independent code (PIC)
gcc -fPIC -c -o xxx.o xxx.c
# Build a shared object and link with static libraries
ld -shared -static -o xxx.so xxx.o
# Same thing but with static libc
ld -shared -static -o xxx.so xxx.o -lc
澄清：静态标志，如果给予gcc，传递给链接器（ld）并告诉它使用库的一个静态版本（.a）（用-l标志指定），而不是动态版本（.so ）。
A clarification: the -static flag, if given to gcc, is passed on to the linker (ld) and tells it to work with the static version (.a) of a library (specified with the -l flag), rather than the dynamic version (.so).
另一件事：在我的系统（Debian）上，最后一个例子给出了一个 libc.a ... recompile with -fPIC 错误。很确定这意味着我在我的系统上的libc.a没有使用-fPIC编译。
Another thing: On my system (Debian) the last example gives a libc.a ... recompile with -fPIC error. Pretty sure that means that the libc.a I have on my system wasn't compiled with -fPIC. An apt-cache search libc pic did give some results however.