绕过System.Windows.Forms.Control的角落?

使用以下代码:

Imports System.Drawing.Drawing2D

Public Class UserControl1
    Private _radius As Int32 = 20
    Private _opacity As Int32 = 125
    Private _backColor As System.Drawing.Color = Color.Black

    Private Sub UserControl1_Paint(ByVal sender As Object, ByVal e As System.Windows.Forms.PaintEventArgs) Handles Me.Paint
        Dim rect As Rectangle = Me.ClientRectangle
        rect.X = rect.X + 1
        rect.Y = rect.Y + 1
        rect.Width -= 2
        rect.Height -= 2
        Using bb As GraphicsPath = GetPath(rect, _radius)
            Using br As Brush = New SolidBrush(Color.FromArgb(_opacity, _backColor))
                e.Graphics.FillPath(br, bb)
            End Using
        End Using
    End Sub

    Protected Function GetPath(ByVal rc As Rectangle, ByVal r As Int32) As GraphicsPath
        Dim x As Int32 = rc.X, y As Int32 = rc.Y, w As Int32 = rc.Width, h As Int32 = rc.Height
        r = r << 1
        Dim path As GraphicsPath = New GraphicsPath()
        If r > 0 Then
            If (r > h) Then r = h
            If (r > w) Then r = w
            path.AddArc(x, y, r, r, 180, 90)
            path.AddArc(x + w - r, y, r, r, 270, 90)
            path.AddArc(x + w - r, y + h - r, r, r, 0, 90)
            path.AddArc(x, y + h - r, r, r, 90, 90)
            path.CloseFigure()
        Else
            path.AddRectangle(rc)
        End If
        Return path
    End Function
End Class

它创建了舍入的用户控件.希望对您有帮助.

It create Rounded User Control.I hope it will help you.

我以前从未做过，但是这些链接可能会对您有所帮助
c-sharp-how-to-add-round-corner- [ ^ ]
圆形按钮窗口形式为c# [ ^ ]
^ ]
我认为也许您应该考虑使用WPF应用程序，因为我相信所有这些对您而言都将容易完成.

Well I have never done this before but these links might help you
c-sharp-how-to-add-round-corner-to-button[^]
rounded button windows form c#[^]
My Google Search[^]
I think maybe you should look into doing a WPF app instead as I believe all this would be a lot easier to accomplish for you.

您必须使用(或创建)自定义控件. Google是您的朋友.

You have to use (or create) a custom control. Google is your friend.