如何在php的sql数据库中存储数据
我已经使用php和jquery创建了注册表.我需要将输入详细信息存储到sql数据库.
I have created register form using php and jquery. I need to store input details to sql database.
我创建了config.php,并将其包含在index.php和Submit.php文件中.
I created config.php and included in index.php and submit.php file.
但是仍然没有存储在数据库中,我可以知道config.php代码中的错误是什么吗,有人可以帮助我吗?
But still didn't store in database, may i know what is my mistake in config.php code, can anyone please help me?
这是我的config.php代码:
This is my config.php code:
<?php
// configuration
$username = "root";
$password = "";
// database connection
$conn = new PDO('mysql:host=localhost;dbname=crop', $username, $password);
$stmt = $conn->prepare("INSERT INTO crop VALUES (:one, :two, :three)");
// values to enter
$data = array(
'one' => 'value one',
'two' => 'value two',
'three' => 'value tree'
);
if ($stmt->execute($data)) echo "Inserted successfully";
?>
那不是做到这一点的方法.您必须使用INSERT语句,而不是SELECT.
Thats not the way to do it. You have to use an INSERT statement, not SELECT.
尝试以下示例:
您必须根据数据库结构更改代码.在这里,我只是假设有一个名为table的表,并且有3个字段.
You have to change the code based on your database structure. In here i just assume there's a table called table and there are 3 fields.
<?php
$stmt = $con->prepare("INSERT INTO table VALUES (:one, :two, :three)");
// values to enter
$data = array(
'one' => 'value one',
'two' => 'value two',
'three' => 'value tree'
);
if ($stmt->execute($data)) echo "Inserted successfully";